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There is an equation for finding out the number of electrons in each shell:

Ne=2n2 and as known 1st shell is called k-shell, 2nd L-shell, 3rd M-shell, and so on, now put the value of each shell in the equation we get Ne(k)=1(1)2 this results in 2 so k-shell has 2 electrons, likewise put the value of each shell in the equation you will get the exact number of electrons in each shell..

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13y ago
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13y ago

Am wondering this myself.... can't seem to find the answer so am assuming it's not known. The onyl thing I can think of is that they are spinning so fast and so close to the "nucleus" that there's no room for any others?..... any one else?

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13y ago

It's all to do with spin and angular momenta, and the way quantum theory works. For any orbital state, there are 2 spin values ("up" and "down"). In that orbital state "l" (letter l) there are (2xl +1) possible orbital sub-states labelled by integers from -l to +l. The smallest "l" you can have is zero (just one state with no orbital momentum at all) and this is called the "K shell". For any orbital sub-state there are the 2 spin states. Since the K shell only has the single orbital state, the only possiblities for electrons are the 2 spin states.

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10y ago

The question seems a bit convoluted because the 2s orbital electrons do not have to only be considred the valence shell. The valence shell pertains to whichever atomic orbital is currently the outermost of of the highest energy. It is a relative term and so the 2s orbital contains only electrons in the outer shell for the elements Li and Be.

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Q: Why s shell have 2 electron in its shells?
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