A sub shell is an area inside an atom's electron shell that contains a type of electron orbital. Each and every atom consists of a central nucleus of one or more positive protons and zero or more chargeless neutrons, with electrons traveling about it the electrons are on shells
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The subshells in the M shell are 3s, 3p, 3d, and 4s. In terms of increasing energy, the order would be 3s < 3p < 3d < 4s.
Your question reveals a common confusion between orbitals and shells. Chlorine has three electron shells: the first, second and third. The first shell has just the one orbital, the 1s The second shell has two sub-shells, the 2s and the 2p. There are three p orbitals in the 2p sub-shell. Each orbital can hold two electrons, so there are eight electrons maximum in the second shell. The third shell likewise has two sub-shells, the 3s and the 3p, but the 3p is not completely filled, leaving room for one more electron. When chlorine gains this electron it will become a Cl- ion. This is summed up in the electron configuration 1s22s22p63s23p5.
M shell notation: N = 3 contains 3 sub shells s,p and d (3s,3p and 3d) *according to my chemistry book.
There are 7 Energy Levels of electrons called shells, and there are 4 sub-shellsnamed as sub-shells s, p, d, and f. They are ordered as 1s - 2s - 2p - 3s- 3p - 4s - 3d - 4p - 5s- 4d - 5p - 6s - 4f - 5d - 6p - 7s - 5f - 6d - 7p - 6f - 7d - 7f. "s" sub-shells consists of 2 electrons, "p" sub-shells consists of 6 electrons, "d" sub-shells consists of 10 electrons, and "f" sub-shells consists of 14 electrons. The first shell has 2 electrons, the second shell has 8 electrons, the third shell has 18 electrons, the fourth shell has 32 electrons, the fifth shell has 50 electrons, the sixth shell has 72 electrons, and the seventh and last shell has 98 electrons. Oh!!! By the way, the formation of the energy levels is like the solar system. The sun is the nucleus and the proton while the Planets are the electrons. There are seven orbits and each orbit has its own electron count. I mentioned it earlier in this answer of mine.
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Four sub-shells: s, p, d, f . Only artificially / theoretically in quantum mechanics there is a 5th sub shell 'g' and maybe 'h' is the 6th
4 s , p , d , 7
-2 Another view the p-shell, one of the 4 sub-shells always represents the outermost shell.
Your question reveals a common confusion between orbitals and shells. Chlorine has three electron shells: the first, second and third. The first shell has just the one orbital, the 1s The second shell has two sub-shells, the 2s and the 2p. There are three p orbitals in the 2p sub-shell. Each orbital can hold two electrons, so there are eight electrons maximum in the second shell. The third shell likewise has two sub-shells, the 3s and the 3p, but the 3p is not completely filled, leaving room for one more electron. When chlorine gains this electron it will become a Cl- ion. This is summed up in the electron configuration 1s22s22p63s23p5.
It belongs to group 11. This is because it has a single electron in the p sub-shell and all inner shells are full.
A break down of 2d1:2 = the quantum energy level or electron shell denoted as 'n'd = the sub-shell of the energy level (known as a degenerate level)1 = the number of electrons occupying the sub-shell.Through extensive research by scientists, no known element has a d sub-shell in the second (n=2) energy level. In fact, the d sub-shell does not appear until the fourth period (fourth row).The first d sub-shell is known to be in the third energy level (therefore the first energy level with this sub-shell is 3d, but not 2d).Transition metals are the elements known to fill the d sub-shells. The first transition metal in the periodic table is scandium (Sc) with the electron configuration of [Ar]4s23d1.The reasons for the formation of sub-shell of d is beyond my knowledge and the scope of basic chemistry.
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NO!
You can tell the difference between a 2s sub-shell and 2p sub-shell from their energy levels, because a 2p sub-shell is a higher energy level than a 2s sub-shell.
The subshells in the M shell are 3s, 3p, 3d, and 4s. In terms of increasing energy, the order would be 3s < 3p < 3d < 4s.