M shell notation:
N = 3 contains 3 sub shells s,p and d (3s,3p and 3d)*according to my chemistry book.
4 because s,p, d, and f are all in the 4th shell as subshells
There are four orbitals of the f subshell. The name of the four f subshells include 4s, 4p, 4d, and 4f. The historical name of the f subshells is called "fundamental subshells".
n=1, 1 subshelln=2, 4 subshellsn=3, 9 subshellsn=4, 16 subshellsSo, you see the trend is n^2 subshells
There are 4 electron sub-shells: s, p, d, and f. These letters stand for sharp, principal, diffuse, and fundamental, but the names are not important. s subshells have 2 electons, while p subshells have 6, d subshells have 10, and f subshells have 14. There can be higher subshells, but these subshells require too much energy to fill and no element with a g subshell (the next subshell after f) has ever been synthesized. The first shell (i.e. the first period of the periodic table) has only s. Thus, the first shell has 2 electrons. The second shell has s and p subshells, so it has 2+6 or 8 electrons. The third shell has s, p, and d subshells. It ultimately has 18 electons. This can be misleading, however. The d subshell requires more energy to fill than the higher-shell s subshell. This is why the third period of the periodic table does not have a d section: the d electron subshell of the third Bohr shell does not fill until after the s subshell of the fourth Bohr shell has filled. Looking at the periodic table, you can see that the third period only has 8 electrons, while the 4th period has 18. The 18 electrons in the fourth period are the s subshell of the fourth shell, the d subshell of the 3rd shell, and the p subshell of the 4th shell. The fourth shell is similar to the third shell, but more extreme. The fourth shell has s, p, d, and f subshells, but the f subshell is not filled until two higher s shells have been filled. It does, however, fill out to 32 electrons in the 6th period of the periodic table. In the 6th period, the first period to have 32 electrons, there are 32 electrons, filling these subshells: s subshell of the 6th shell, f subshell of the 4th shell, d subshell of the 5th shell, and then the p subshell of the 6th shell. The fifth shell would ultimately fill out to a full 50 electrons and would do so in the 8th period of the periodic table. However, as previously noted, no substance has ever been found or generated with that many electrons. It would fill the s subshell of three shells above (i.e. shell 8) before it filled the g subshell of shell 5. No element in the 8th period has ever been synthesized, so a filled fifth Bohr shell has never been found. A good example for a Bohr diagram would be Astatine, which is in the 6th period. In the first shell of the Bohr diagram, you have 2 electrons (s subshell only). It is filled completely. In the second, you have 8 electrons (s and p subshells) and in the third you have 18 electrons (s, p, and d), and both shells are filled completely. In the fourth shell, you have 32 electrons (s, p, d, and f), and it is filled completely. In the fifth shell, you have 18 electrons. This is because only the s, p, and d subshells are filled. It would require too much energy to fill the f subshell of the 5th shell, so the electrons just go to the s, p, and d subshell of higher shells. The 6th shell has 7 electrons. The 2 electrons of the s subshell are filled first, and then 5 electrons go into the p shell.
The number of electrons depend on the principal quantum number. For n=1 the maximum number of allowed electrons is 2. And the values are 8 and 18 for n=2 and n=3 respectively. When n>3, the maximum electrons allowed in the shell is 32.
3
4 because s,p, d, and f are all in the 4th shell as subshells
If your are talking about s shell search then # of subshells equals n-1. So if n=3 the number of subshells is two. If your are talking about periodic chemistry the number of subshells for n=3 is six. If your are talking about the Weriner progression then ss= n!/(n-3)!
Subshell or Subshells
4. 1st shell: s subshell 2nd shell: s and p subshells 3rd shell: s, p and d subshells 4th shell: s, p, d and f subshells
The number of electrons in the lowest electron shellis2 in the first or K shell (subshell 1s)---For other shells, the maximum is determined by the formula 2n2:2) 8 in the L shell (subshells 2s, 2p)3) 18 in the M shell (subshells 3s, 3p, 3d)4) 32 in the N shell (subshells 4s, 4p, 4d, 4f)5) 50 in the O shell (subshells 5s, 5p, 5d, 5f, 5g*)6) 72 in the P shell (subshells 6s, 6p, 6d, 6f, 6g, and an unnamed subshell)7) 98 in the Q shell (subshells 7s, 7p, 7d, 7f, 7g, and two unnamed subshells)* the highest existing subshells are 5f, 6d, and 7s* the highest currently predicted subshells are 7p and 8s* no existing element has more than 32 electrons in any shellThe maximum per subshell is determined by the formula 2(2L+1) (s is 0):s subshells can have 2 electronsp subshells can have 6 electronsd subshells can have 10 electronsf subshells can have 14 electronsg subshells can have 18 electrons*There are no elements with electrons past the f subshell, so the shells with 22 and 26 electrons have no name. The largest element created (Roentgenium, element 111) has 2 electrons in the 7s shell.
There are four orbitals of the f subshell. The name of the four f subshells include 4s, 4p, 4d, and 4f. The historical name of the f subshells is called "fundamental subshells".
A subshell is a subdivision of electron shells.
n=1, 1 subshelln=2, 4 subshellsn=3, 9 subshellsn=4, 16 subshellsSo, you see the trend is n^2 subshells
Ionic Method or Half Shell Notation.... the symbol is shown and the electrons are distributed on the different energy levels represented by half-shell
There are 4 electron sub-shells: s, p, d, and f. These letters stand for sharp, principal, diffuse, and fundamental, but the names are not important. s subshells have 2 electons, while p subshells have 6, d subshells have 10, and f subshells have 14. There can be higher subshells, but these subshells require too much energy to fill and no element with a g subshell (the next subshell after f) has ever been synthesized. The first shell (i.e. the first period of the periodic table) has only s. Thus, the first shell has 2 electrons. The second shell has s and p subshells, so it has 2+6 or 8 electrons. The third shell has s, p, and d subshells. It ultimately has 18 electons. This can be misleading, however. The d subshell requires more energy to fill than the higher-shell s subshell. This is why the third period of the periodic table does not have a d section: the d electron subshell of the third Bohr shell does not fill until after the s subshell of the fourth Bohr shell has filled. Looking at the periodic table, you can see that the third period only has 8 electrons, while the 4th period has 18. The 18 electrons in the fourth period are the s subshell of the fourth shell, the d subshell of the 3rd shell, and the p subshell of the 4th shell. The fourth shell is similar to the third shell, but more extreme. The fourth shell has s, p, d, and f subshells, but the f subshell is not filled until two higher s shells have been filled. It does, however, fill out to 32 electrons in the 6th period of the periodic table. In the 6th period, the first period to have 32 electrons, there are 32 electrons, filling these subshells: s subshell of the 6th shell, f subshell of the 4th shell, d subshell of the 5th shell, and then the p subshell of the 6th shell. The fifth shell would ultimately fill out to a full 50 electrons and would do so in the 8th period of the periodic table. However, as previously noted, no substance has ever been found or generated with that many electrons. It would fill the s subshell of three shells above (i.e. shell 8) before it filled the g subshell of shell 5. No element in the 8th period has ever been synthesized, so a filled fifth Bohr shell has never been found. A good example for a Bohr diagram would be Astatine, which is in the 6th period. In the first shell of the Bohr diagram, you have 2 electrons (s subshell only). It is filled completely. In the second, you have 8 electrons (s and p subshells) and in the third you have 18 electrons (s, p, and d), and both shells are filled completely. In the fourth shell, you have 32 electrons (s, p, d, and f), and it is filled completely. In the fifth shell, you have 18 electrons. This is because only the s, p, and d subshells are filled. It would require too much energy to fill the f subshell of the 5th shell, so the electrons just go to the s, p, and d subshell of higher shells. The 6th shell has 7 electrons. The 2 electrons of the s subshell are filled first, and then 5 electrons go into the p shell.
The number of electrons depend on the principal quantum number. For n=1 the maximum number of allowed electrons is 2. And the values are 8 and 18 for n=2 and n=3 respectively. When n>3, the maximum electrons allowed in the shell is 32.