Just about 6.022 X 1023 atoms of sulfur. Sulfur is 32.07 grams per mole.
Sulfur's atomic weight of 32.065 amu's represents a weighted average of the masses of all the naturally occurring isotopes of sulfur (weighted by how common the isotope is in nature). Those isotopes are: S-32 Mass = 31.972 amu Abundance = 95.02% S-33 Mass = 32.971 amu Abundance = 0.75% S-34 Mass = 33.968 amu Abundance = 4.21% S-36 Mass = 35.967 amu Abundance = 0.02% 32.065 = (31.972*0.9502) + (32.971*0.0075) + (33.968*0.0421) + (35.967*0.0002) Mass and abundance data was taken from the '91 CRC Handbook.
Add up the number of protons and neutrons.
This question contains its own answer, because "g" is an abbreviation for grams!
For the same reason other isotopes of other elements are the most abundant. They are the most stable.
Approximately 5.3469152 * 10^-23
32 grams
Sulfur Trioxide has a molar mass of 80.0632 grams per mole. Therefore, 6.11 moles of Sulfur Trioxide is 489.186152 grams (without significant figures). With significant figures that would be 489 grams.
A sulfur molecule has the formula S8. Multiply the number of sulfur atoms (8) times the atomic weight of sulfur in grams (32.065g). The molar mass of S8 = 256.52g S8.
From the periodic table, calcium has a molar mass of 40.078g/mol and sulfur has a molar mass of 32.065g/mol. The formula for compound formed from calcium and sulfur, calcium sulfide is CaS. The molar mass of CaS is 72.143. So, if you round the numbers, 40g of Ca + 32g of S will produce 72g of CaS.
Multiplying moles of S by molecular mass of it (Sulfer: 32.06 g/mole) gives mass in grams0.0458 mole * 32.06 g/mole = 1.47 g Sulfur
For this you need the atomic mass of S. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel.2.4 mole S × (32.1 grams) = 77.0 grams S
Sulfur Trioxide has a molar mass of 80.0632 grams per mole. Therefore, 6.11 moles of Sulfur Trioxide is 489.186152 grams (without significant figures). With significant figures that would be 489 grams.
The mass of sulfur is 50,04 g.
Sulfur has relative atomic mass of 32 and oxygen have that of 16. The molar mass of sulfur dioxide is 64 grams per mole. Therefore there is approximately 0.58 moles (37.14/64) of sulfur dioxide in given weight.
The mass of sulfur is 6,118 g.
It is 32.06 grams.
moles = mass / molar mass assuming that sulfur is simply represented by "S", then the molar mass is 32.07, as seen in the periodic table (meaning that each sulfur atom is 32.07 grams per mole. so moles of sulfur = 80.25 / 32.07 = 2.50 moles
A sulfur molecule has the formula S8. Multiply the number of sulfur atoms (8) times the atomic weight of sulfur in grams (32.065g). The molar mass of S8 = 256.52g S8.
The mass is 11 g.
Sulfur is a non meta element. Atomic mass of it is 32.
For this problem, the atomic mass is required. Take the mass in grams and divide it by the atomic mass. Then multiply it by Avogadro's constant, 6.02 × 1023.3.86 grams S / (32.1 grams) × (6.02 × 1023 atoms) = 7.24 × 1022 atoms
From the periodic table, calcium has a molar mass of 40.078g/mol and sulfur has a molar mass of 32.065g/mol. The formula for compound formed from calcium and sulfur, calcium sulfide is CaS. The molar mass of CaS is 72.143. So, if you round the numbers, 40g of Ca + 32g of S will produce 72g of CaS.
Multiplying moles of S by molecular mass of it (Sulfer: 32.06 g/mole) gives mass in grams0.0458 mole * 32.06 g/mole = 1.47 g Sulfur