series network consists of components i.e resisters connected end to end. since their is only one path for the flow of current. but potential drop across each resister is different. so thats the reason that series network has maximum resistence then the highest resister in combination. the same amount of current passes through each resister.
The net resistance can be found out using the algebraic sums f series and parallel connections. When there is no current flowing in the circuit the net resistance is infinite.
In brief, the overall or net resistance changes and the resistors in series and/or parallel can be represented by a single equivalent resistor. If you consider series resistors the equivalent resistance of the series would be: R = R1+R2+ ... +Rx The equivalent resistance of parallel resistors would be: 1/R = 1/R1 + 1/R2 + ... + 1/Rx One rule to always remember when dealing with series and parallel resistors is the voltage across each resistor in parallel will be the same as defined in Kirchhoff Voltage Law and the current across each resistor in series will be the same by Kirchhoff Current Law. More information can be found at this web site. http://physics.bu.edu/py106/notes/Circuits.html
The net effective resistance of 5 ohms, 10 ohms, and 20 ohms in series is 35 ohms.The current through the net effective resistance is [ I = E/R ] = 120/35 = 3.429 Amp. (rounded)Note: If you try this at home, be aware that these resistors will dissipatethe 5 ohm . . . 58.8 wattsthe 10 ohm . . . 117.6 wattsthe 20 ohm . . . 235 watts .These are no ordinary resistors, such as hang on the wall in plastic bags at Radio Shack.These would have to be 'power' resistors ... like heating coils in a toaster or hair-dryer.
assume the following configuration: battery connected to 2 parallel resistors with an ammeter in series with the battery... observe the current measurement ... remove one of the resistors .... observe the current again, it will have decreased: if the resistors were of equal value, the current will decrease to half of its original value when one of the resistors is removed. Mathematics: V=IR (V- voltage, I - current, R - resistance in a parallel circuit, R=(R1*R2)/(R1+R2) where R1 and R2 are the values of resistance of the resistors. Before removal- Ib=V*(R1+R2)/(R1*R2) After removal (assume R2 is removed)- Ia=V/R1 so Ia/Ib=(R1*R2)/(R1*(R1+R2)) or Ia=Ib*(R2/(R1+R2) if R1=R2 then Ia=Ib*R2/(2*R2) or Ia=Ib/2 so the current after is 1/2 of that before.
The net effective resistance of the parallel devices is the reciprocal of (1/12 + 1/4). Hence 3 ohms.=============================================(Which actually looks strangely similar to the first answer above.Could it be just coincidence ? I wonder . . . )
The net resistance of two resistors connected in series is the sum of the two resistances. RSERIES = Summation1toN RN
The net effective resistance of resistors in series is the sum of the individuals.Combined resistance = (100,000,000) + (10) = 100,000,010Ωhms.
The net resistance can be found out using the algebraic sums f series and parallel connections. When there is no current flowing in the circuit the net resistance is infinite.
The weight exceeds the force of air resistance, but as the speed increases the air resistance increases, so the net force (weight - air resistance) falls. When the difference becomes zero the acceleration ceases and you have terminal velocity.
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The amount of friction increases.
net profit will increase
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The word "falling" implies there is a gravitational force also. As the object gains speed, the air resistance ("drag") increases, until it equals the gravitational force. After that there is no net (resultant) force, so the object goes at constant speed.
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No.