0
the reason is certainly related to the fact that the speech is put in frame of 20ms. And when the GSM was invented, 20ms could be encoded/compressed/etc. into 4x0.577 ms.
20ms => 4x0.577ms = 2.3ms
each 20ms, one user needs 2.3ms.
So during 20ms on the air, only 8 calls can be multiplexed.
20/2.3 = 8.7
The remaining is used for in band signalling (sacch).
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How many timeslots are in TRX of GSM?
8 time slots
Why is a TDMA frame equal with 4.615ms?
1 frame = 8 timeslots (0 to 7) of approximately 577 μs duration with 156.25 bits per timeslot. The duration of 1 frame = 577 μs X 8 = 4615 μs = 4.615 ms ...Engr. Adakole Ogbole
What is Extended BCCH frame structure in GSM?
4
What is 280 microns into gsm?
8
What is the marketing strategy of safeguard soap?
national commercials bid on timeslots use a slogan
Difference between e1 and t1 in telecommunication?
Differing Characteristics :-In E1 Encoding/Decoding is followed by A-Lawwhile in T1 Encoding/Decoding is followed by µ-Law.In E1 - 13 Number of Segments in Characteristicswhile in T1 - 15 Number of Segments in Characteristics.In E1 - 32 Number of Timeslots / PCM Framewhile in T1 - 24Number of Timeslots / PCM Frame.In E1 - 8 x 32 = 256 number of bits / PCM Frame while in T1 - 8 x 24 + 1* = 193 number of bits / PCM Frame. (* Signifies an additional bit).In E1 - (125µs x 8)/256 = approx 3.9µs is the length of an 8-bit Timeslot while in T1 - (125µs x 8)/193 = approx 5.2µs is the length of an 8-bit Timeslot.In E1 - 8000/s x 256 bits = 2048kbit/s is the Bit Rate of Time-Division Multiplexed Signal while in T1 - 8000/s x 193 bits = 1544kbit/s is the Bit Rate of Time-Division Multiplexed Signal.
The number of utilizable carriers in GSM 900 is?
8
Is a picture frame 8 x 6 the same as a picture frame 6 x 8?
no
Use of GSM phone?
yes you can do it it's simple
Are gsm use sfh to improve signal?
Frequency Hopping is an old technique introduced firstly in military transmission system to ensure the secrecy of communications and combat jamming. Frequency Hopping is mechanism in which the system changes the frequency (uplink and downlink) during transmission at regular intervals. It allows the RF channel used for signaling channel (SDCCH) timeslot or traffic channel (TCH) timeslots, to change frequency every TDMA frame (4.615 ms). The frequency is changed on a per burst basis, which means that all the bits in a burst are transmitted in the same frequency.
What method can you use to determine the circumference of a picture frame that is 8 inches?
The answer will depend on whether the 8 inches refers to the radius or the diameter of the frame.
How many customers are served by one E1?
one E1 link can be splitted into 32 links by internal boards in BSC. one link generates 64Kpbs so 32 links produces 2.048Mbps signal ( 32x64Kbps=2040Kbps). 1 E1 link splitted to 32 links by boards, and each link has got 8 Timeslots, totally 32x8=256 Timeslots, Means 256 Users can utilize at a time. But, In practice people may use packet calls also, So the whole frame structure cannot be given to Voice circuits. Keeping this in mind we again split the links into Ports such as primay and secondary. primary which is given to Circuit switching and secondary for packet switching. We can assign the timeslots for CS & PS manually depends on the services and operator demand. Eventhough 256 users can utilize, we are using apprx 128 by one E1 link. (16x64Kbps). The circuit switching timeslot figure can be more than 128 sometimes because packet calls requires higher data always. So many of the service providers can have more timeslots for voice than packet switching technique. hope am right. if you find the mistakes pl correct me. Thank you !!!!
