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This can easily be understood with conservation of energy. Assuming that no energy is lost, potential energy is continuously converted to kinetic energy, and vice versa. At the mean position, the potential energy is zero, therefore the kinetic energy (and hence the velocity) is at maximum.

This can easily be understood with conservation of energy. Assuming that no energy is lost, potential energy is continuously converted to kinetic energy, and vice versa. At the mean position, the potential energy is zero, therefore the kinetic energy (and hence the velocity) is at maximum.

This can easily be understood with conservation of energy. Assuming that no energy is lost, potential energy is continuously converted to kinetic energy, and vice versa. At the mean position, the potential energy is zero, therefore the kinetic energy (and hence the velocity) is at maximum.

This can easily be understood with conservation of energy. Assuming that no energy is lost, potential energy is continuously converted to kinetic energy, and vice versa. At the mean position, the potential energy is zero, therefore the kinetic energy (and hence the velocity) is at maximum.

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14y ago

This can easily be understood with conservation of energy. Assuming that no energy is lost, potential energy is continuously converted to kinetic energy, and vice versa. At the mean position, the potential energy is zero, therefore the kinetic energy (and hence the velocity) is at maximum.

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Q: Why velocity of a mass attached to a spring is maximum at mean positions and zero at extreme positions?
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