yes
No, but interestingly spearmint does at a temperature of 73.48 degrees celsius, 164.264 degrees fahrenheit.
It is water.
no
I am assuming by "sugar content" you are referring to a solution of sugar and water. Water at around 25 degrees Celsius has a density of 1.0 gram/cm3. The density of solid sugar (sucrose) is around 1.6 grams/cm3. As you dissolve sucrose in water, the density of the resulting solution will naturally increase as you add more and more sugar. As you approach 100% sucrose, the density will approach 1.6 grams/cm3.
67.0 grams of caffeine will dissolve in 100 mL of water at 100 degrees Celsius. 100mL of water = 100g of water so.. 67.0 grams of water will dissolve in 100 grams of water at 100 degrees Celsius. I pretty sure this is right, I was searching for the answer myself and it seems to work. But more accurately you will need to find the density of water at 100 ºC which is 0.9584 g/mL. So, 100g/0.9584 g/mL equals about 104 mL. Then 104 mL x 67.0g/100 mL = 69.9 g.
Aproximately 4 grams of potassium chlorate will dissolve in 50 g of water at 20 degrees celsius.
No, but interestingly spearmint does at a temperature of 73.48 degrees celsius, 164.264 degrees fahrenheit.
No, sugar has a melting point of 161 degrees Celsius and salt has a melting point of 801 degrees Celsius
222g/100g H2O at 20 degrees Celsius
yes there was
It is water.
no
Sucrose is the most soluble.
I am assuming by "sugar content" you are referring to a solution of sugar and water. Water at around 25 degrees Celsius has a density of 1.0 gram/cm3. The density of solid sugar (sucrose) is around 1.6 grams/cm3. As you dissolve sucrose in water, the density of the resulting solution will naturally increase as you add more and more sugar. As you approach 100% sucrose, the density will approach 1.6 grams/cm3.
67.0 grams of caffeine will dissolve in 100 mL of water at 100 degrees Celsius. 100mL of water = 100g of water so.. 67.0 grams of water will dissolve in 100 grams of water at 100 degrees Celsius. I pretty sure this is right, I was searching for the answer myself and it seems to work. But more accurately you will need to find the density of water at 100 ºC which is 0.9584 g/mL. So, 100g/0.9584 g/mL equals about 104 mL. Then 104 mL x 67.0g/100 mL = 69.9 g.
Well, heating a cup of water would allow it to dissolve more of a particular substance if that is what you mean (given that the solute is able to dissolve in a polar solvent at all). For example, if you have two cups of equal volumes of water, one at 20 degrees celsius and the other at 35 degrees celsius, the water at the higher temperature (35 degrees celsius) would be able to dissolve more salt that the water at the lower temperature.
According to the Wikipedia article on sucrose, the solubility of sucrose in water is 2000g/L at 25 degrees Celsius. Because the density of pure water is 1g/mL, 200 grams of pure water would be 200mL of water, which in turn is 0.200L of water. 2000g/L sucrose x 0.200L water = 400g of sucrose So, at 25 degrees Celsius, 400g of sucrose can dissolve in 200g of water.