Well, I think it will swing faster in the equator than at the poles because T=sq. root l/q says that when the gravity increases, the time decreases and when the gravity decreases time increases. Thus it will swing slower at the poles than in the equator
A pendulum will swing slowest when closest to the equator. Why is this? The time period, T, of the swing of a pendulum is given by: T=2π√(l/g) where l is the length of the pendulum and g is acceleration due to gravity. Because the Earth is spinning, there is a bulge at the equator and the poles are slightly flattened. Hence on the equator the radius to the centre of the earth is greater than the radius at the poles. The equatorial radius is 6378.1km while the polar radius is 6356.8 km The value of g at the Earth's surface relates to the values of the Earth's radius, r, at that point using an inverse square law ie g is proportional to 1/r2 At the North Pole, g is about 9.83m/s2, while at the equator, g is smaller, at only 9.79m/s2 . So the period of a pendulum will be longer (i.e. slowest) at the equator than at the pole
A pendulum moves not by Earth's rotation, but by gravity pulling down and causing it to swing.
At the low point of a swinging pendulum, the type of energy being demonstrated is maximum kinetic energy. It has zero potential energy at this point of the swing.
Galileo's pendulum experiment showed that the period of the swing is independent of the amplitude (size) of the swing. So the independent variable is the size of the swing, and the dependent variable is the period. The experiment showed there was no dependence, for small swings anyway. The experiment led to the use of the pendulum in clocks.
You're referring to the Foucault Pendulum. If you can keep any pendulum swinging long enough without it dying out, you'll see that the 'plane' of its swing rotates ... if you start it out swinging between the left and right walls of the room, then it slowly turns to swing between the front and back walls, and eventually comes back around to the left and right walls again. The time it takes to rotate depends on the latitude of your location. The shortest possible period is 24 hours ... that happens with a pendulum at the north and south poles. At the latitude of Glasgow or the tip of South America, it's about 29 hours; at the latitude of Caracas Venezuela or Lima Peru, it's over 130 hours; at the equator, it doesn't rotate at all.
If the pendulum was pushed with a large force or if it was heavier. It might swing faster.
By shorten the string of the pendulum
A pendulum will swing slowest when closest to the equator. Why is this? The time period, T, of the swing of a pendulum is given by: T=2π√(l/g) where l is the length of the pendulum and g is acceleration due to gravity. Because the Earth is spinning, there is a bulge at the equator and the poles are slightly flattened. Hence on the equator the radius to the centre of the earth is greater than the radius at the poles. The equatorial radius is 6378.1km while the polar radius is 6356.8 km The value of g at the Earth's surface relates to the values of the Earth's radius, r, at that point using an inverse square law ie g is proportional to 1/r2 At the North Pole, g is about 9.83m/s2, while at the equator, g is smaller, at only 9.79m/s2 . So the period of a pendulum will be longer (i.e. slowest) at the equator than at the pole
If it is a short pendulum, then the leg or whatever you call it has a smaller distance to cover, and therefore can swing faster than a longer pendulum.
A heavier pendulum will swing longer due to its greater inertia.
how is pendulum swing related to teaching process?
A simple pendulum.
The acceleration of a pendulum is zero at the lowest point of its swing.
no the bob on the shorter one has less distance per period to travel
no the bob on the shorter one has less distance per period to travel
me
momentum