R = V / I (Ohms Law) A greater voltage results in more current. In the particular case of a light bulb, the resistance will change with current because its temperature changes. We assume here that the bulb is rated to take 200V.
This is not an easy question to answer. The reason for this is that the resistance of a tungsten filament increases by a factor of 10 - 18 from its 'cold' temperature to its operating ('hot') temperature. And, of course, you don't mention which voltage is the rated voltage of the lamp. So, without knowing the lamp's resistance at each of these voltages, it is difficult to determine which voltage would result in the lower current.
Provided the higher voltage doesn't burn out the filament (by exceeding its power rating), then the higher voltage will result in a higher current.
When you put a light bulb in series with a inductor, the inductive reactance of the inductor reduces the current available to the light bulb, making it less bright. For this effect to be noticed, however, you need a very large inductor. To cut the current in a 60W bulb at 120VAC/60Hz by one half, for instance, you need an inductor around 0.6 henrys.
How much what? Power? 102mW (0.102W). How much light? A filament bulb produces 1 to 3 percent of the power input as light if the proper voltage is applied. If the lamp is rated for a higher voltage, it won't get hot enough and the light out will be a lot less.
When three light bulbs are in parallel the voltage V on each is the same. Each bulb draws a certain amount of current, i1, i2, & i3. If all three are working they draw a total current I = i1 + 12 + 13 from your power source. And the energy they use is ,I x V. When one bulb goes out then the only thing affected is i3 = 0. The voltage is the same but the total current from your power source is less and therefore the total energy used is less. So nothing happens to the other two bulbs (that's one reason why all household outlets are in parallel) and you just use less energy.
If the bulbs are in parallel, other bulbs aren't affected, so I guess you mean a series circuit. A string of light bulbs connected in series (like a Christmas light string) connected to a specific supply voltage can be visualised as a string of rubber bands, knotted to each other in a line, and stretched to a specific distance. If all the rubber bands are the same, they will all stretch equally, i.e. if all bulbs are the same, they will all have the same voltage across them. Increasing the resistance of one bulb is like making one rubber band thinner than the others, and you can imagine what will happen. The thin rubber band will stretch more than the others, and the others will take up the slack and become a bit shorter, i.e. the bulb with higher resistance will have more voltage across it, and the remaining bulbs will have slightly less than before. The current (i.e. the tension in the string of rubber bands) reduces slightly. Looking at the power dissipation for that light bulb, which is voltage x current, voltage will increase, and current will drop slightly, so the overall effect is that the bulb with the higher resistance will dissipate more power than the others.
A light bulb (called a lamp by the industry) will emit light when a voltage is applied to it. The applied voltage causes current flow through the lamp, and the lamp responds by emitting light. (There are many different lamps and they work differently, and we're generalizing here.) The lamp doesn't care whether the voltage that drive current through it comes from. It responds to the voltage (and current flow) according to its rating. If a given voltage is nominal for a lamp under inspection and we apply that, that lamp can be powered up by a generator, a battery, solar cells, or a number of other sources. Apply the appropriate voltage, and the lamp responds.
It will be greater:current = voltage / resistanceSince the bulb's resistance doesn't change, then current is a direct function of voltage.
Since an incandescent light bulb is an appliance that has a fixed electrical resistance, operating it at less than its rated voltage means that it will draw less than its rated current and will produce less light.
Let's examine what it means when a bulb is 100W rather than 60W. I'm assuming that you meant to state that they are 120V bulbs being connected to a 240V circuit1. With the same voltage on each, and because power is voltage times current, the current must be greater in a 100W bulb than in a 60W bulb. Since a incandescent bulb is a linear load, if you double the voltage then you double the current2. So the current through the 100W bulb is still greater than through the 60W bulb. Or you may analyze it a bit more. With both on 120V, for more current to flow in the 100W bulb, the resistance of it must be less than that of the 60W bulb. So you may generalize that under any voltage (same voltage applied to each), the 100W bulb will always have more current through it than the 60W bulb. 1Actually, if they are 120V bulbs in a 240V circuit, there is a high probability that they will blow out. But before they do, this is what will happen. 2Well, slightly less than double, because the temperature coefficient on the filament is positive, so the hotter it is, the greater the resistance. Although this may seem nonlinear, a light bulb or other temperature sensitive resistive element is still defined as linear if over the short term it obeys Ohms law at any instant of the waveform. The current in the 100 watt bulb will be greater. Power is current times voltage, so current is power divided by voltage. Voltage is the same is both cases of this question, so current is proportional to power at 240V.
The early light bulb used a rather powerful electric current, Did not have a very good vacuum inside it and in some did not use a bulb at all! Today's light bulbs use less electricity and have no oxygen inside them. This makes them more efficient and reliable.
When you put a light bulb in series with a inductor, the inductive reactance of the inductor reduces the current available to the light bulb, making it less bright. For this effect to be noticed, however, you need a very large inductor. To cut the current in a 60W bulb at 120VAC/60Hz by one half, for instance, you need an inductor around 0.6 henrys.
In a T* ballast and T8 bulb more energy efficient then a T12 ballast and a T8 bulb? A:Depends on the CURRENT through the tube. When the Tube is run at 100% of rating, The T12 Takes more CURRENT to give a certain Brightness. Because the surface of the T8 is closer to the ion stream through the tube, it takes less CURRENT to light up the T8 to the same brightness. However, IF you use a T12 in a T8 ballast, you will get LESS CURRENT through the tube, and LESS POWER consumed ALONG with LESS Light.
By adding more light bulbs
That depends on the type of bulb AND on it's power usage. An old incandescent bulb of 100 watts uses about an amp, a 60 watt uses about a half amp. But a florescent bulb putting out the same light would consume about half the current, and a LED bulb would use less than half that.
A: The current is not a function of voltage available but rather the power needed to light the lamp. To answer your question a 100 watts lamp will require 1.83 times more current for a lamp rated as 100 watts at 120 volts.It is a basic ratio 220:120AnswerI disagree with the previous answer. The power rating of a lamp only applies when the lamp is subject to its rated voltage -which is why both values are shown on the lamp (e.g. 60 W / 120 V).So, if you subject a lamp to less than its rated voltage, it will not achieve its rated power. In fact, the decrease in power will be significantly greater than the corresponding decease in voltage. It will certainly not 'compensate' by drawing more current!However, to directly answer your question, the current drawn by a lamp connected to a 220-V supply will indeed be greater than the current drawn by the same lamp connected to a 110-V supply.
The resistance of a light bulb is inversely proportional to its temperature, i.e. a cold bulb has less resistance than a hot bulb. As a result, if you connect three bulbs in series to the same voltage used for one, they will each receive one third of the original voltage, causing them to use less power, causing them to generate less heat, causing them to have less resistance. If you measure the current in the circuit, there will be slightly more than one third of the original current. Given the same voltage, that means that each bulb has less resistance than originally measured, as expected. This characteristic of light bulbs is why they tend to blow out at turn-on. The starting current and power is higher than in the steady state case. You can make a bulb last much longer if you provide a soft start circuit that ramps up the voltage over a short period of time.
How much what? Power? 102mW (0.102W). How much light? A filament bulb produces 1 to 3 percent of the power input as light if the proper voltage is applied. If the lamp is rated for a higher voltage, it won't get hot enough and the light out will be a lot less.
incandscent light bulbs voltage is 120 wattage is100 light output is 1560 lumens,use resistance as a function of temperature