Commercial vinegar freezes at 28 degrees Fahrenheit. The reason that vinegar freezes at a lower temperature than water is the acid content.
It freezes at -2 degrees c and 28 degrees f .
To be 4 real vinegar doesnt have an melting point so.........
it is not melting you mug its evaporating
The freezing point become lower.
Yes, it would lower it.
28F, -2C
it is 123
Higher the concentration of the solute, lower is the freezing point.
Salt decreases the freezing point of water and increases the boiling point of water.
raise its freezing point
3200ppm would have no affect on the freeze point of water, so your answer would be 32 degrees.
Adding salt (sodium chloride) the freezing point of water decrease; for an experiment add gradually salt (in known quantities) and measure the freezing point after each addition.
Vinegar will not affect the freezing point of vinegar.
Yes because it is no longer water so will have a different freezing time or point
Higher the concentration of the solute, lower is the freezing point.
Atmospheric pressure and the presence and concentrations of solutes affect the freezing point.
The freezing point of water solutions containing sodium chloride is lower.
i would opt for the Freezing point. salt decreases the freezing point of water. so if water would normally freeze at 0C, saltwater would freeze at -3C.
Salt decreases the freezing point of water and increases the boiling point of water.
Increasing the concentration of sodium chloride in water the freezing point is lower.
raise its freezing point
Well, I did an experiment in class on this question. We used different amounts lauric acid and it turned out that the freezing point was pretty much the same for all the samples. So, in all, the freezing point does not depend on the mass of a substance.
It doesn't.
The FREEZING POINT ----- which for a pure substance (as opposed to a mixture)is the same thing as the melting point since they are both the point at which the liquid phase of a substance would be in equilibrium with the solid. For a mixture, the two would be different and you would get a freezing point range that started at the freezing point and ended at the melting point