Write Java program to display largest of 3 numbers?

Answer 1

//i hope its something like this you want

import java.util.*;

public class Count

{

public static void main(String args[])

{

double numbers;

Scanner scan;

int counter;

numbers=0;

scan=new Scanner(System.in);

for(counter=1; counter<=10; counter++)

{

System.out.println("Please enter numbers");

numbers=scan.nextDouble();

{

System.out.println("The number is "+numbers++);

}

}

}

}

Answer 2

#include
#include
int main()
{int a[10];
printf("enter 10 numbers:\n");
for(int i=0;i<=9;i++)
{printf("enter %d number\n",i+1);
scanf("%d",&a[i]);
}
printf("NUMBER SQUARE\n");
for(int j=0;j<=9;j++)
{printf("%d %d\n",a[j],(a[j]*a[j]));
}
getch();
return 0;
}

Answer 3

I would use an array here, since this can easily be extended to more than 3 numbers. Something like this (assuming you already created the array):

maxValue = myArray[1];
for (int i = 1; i < myArray.length(); i++)
if (myArray[i] > maxValue)
maxValue = myArray[i]

Answer 4

CLS

PRINT "PROGRAM: Add up 10 numbers entered from the keyboard;"

PRINT " then, printout their sum total."

PRINT

sumTotal = 0

FOR eachNo% = 1 TO 10

IF eachNo% < 10 THEN PRINT " ";

PRINT eachNo%; "> ";

INPUT "Enter number: ", number

sumTotal = sumTotal + number

NEXT

PRINT

PRINT "The sum total of your 10 numbers is: "; sumTotal

END