Write a program using c plus plus to check whether the given square matrix is symmetric or not?

Answer 1

means whether the matrix is same or not

program for symmetric matrix :

include<stdio.h>

#include<conio.h>

main()

{

int a[10][10],at[10][10],k,i,j,m,n;

clrscr();

printf("enter the order of matrix");

scanf("%d %d",&m,&n);

printf("enter the matrix");

for(i=0;i<m;i++)

{

for(j=0;j<n;j++)

scanf("%d",&a[i][j]);

}

for(i=0;i<m;i++)

{

for(j=0;j<n;j++)

at[i][j]=a[j][i];

}

for(i=0;i<m;i++)

{

for(j=0;j<n;j++)

{

if(at[i][j]!=a[i][j])

k=1;

}

}

if(k==1)

printf("not symmetric");

else

printf("symmetric");

getch();

}

Answer 2

First we find transpose of a matrix and then compare it with the original matrix. For a symmetric matrix A^T = A.

• Step 1 - Accepts a square matrix as input
• Step 2 - Create a transpose of a matrix and store it in an array
• Step 3 - Check if input matrix is equal to its transpose or not

  If it is equal, then the input square matrix is symmetric.

Please find the program attached to find the matrices symmetricity.

To find whether a matrix symmetric or not we can use the following code:

for(i=0;i

for(j=0;j

if(a[i][j]!=a[j][i])

{ch='n';}

Answer 3

1. #include
2. using namespace std;
3. const int MAXROW = 10;
4. const int MAXCOL = 10;
5. int main()
6. {
7. srand(time(NULL));
8. int a [MAXROW][MAXCOL];
9. for (int row = 0; row < MAXROW; row++)
10. {
11. for (int col = 0; col < MAXCOL; col++)
12. {
13. a[row][col] = rand() % 10;
14. cout << a[row][col]<< "\t";
15. if (a[row][col] == a[col][row])
16. cout << "Symmetric" << endl;
17. else
18. cout << "Not symmetric" << endl;
19. }
20. cout << endl;
21. }
22. return 0;
23. }