Write a C program to print numbers from 1 to 999 in words?

Answer 1

write a c program which reads an integer value from the keyboard then it displays the number in words?

#include<stdio.h>

#include<conio.h>

void main(void)

{

int rev,n,

clrscr();

printf("\n enter any number");

scanf("%d",&n);

temp=n;

while(n>0)

{

rem=temp%10;

rev+=rem*10;

temp=temp/10;

choice=rev%10;

switch(choice)

{

case 1:

printf("one");

break;

case 2:

printf("two");

break;

case 3:

printf("three");

break;

case 4:

printf("four");

break;

case 5:

print("five");

break;

case 6:

printf("six");

break;

case 7:

printf("seven");

break:

case 8:

printf("eight");

break:

case 9:

printf("nine");

}

getch();

}

Answer 2

#include
#include
void one(int m)
{ int n;
n=m%10;
switch(n)
{ case 1:printf("One");
case 2:printf("Two");
.
.
.
case 9:........
}
}
void ten(m)
{ int a=m%10;
switch(m)
{ case 11:printf("Eleven");
........
case 15:....
}
if(m>15 && m<20)
{ one(a);
printf("teen");
}
else if(m>=20 && m<30)
{ printf("Twenty");
one(a);
}
else if(m>=30 && m<40)
{..........
}
..........
else
{ printf("Ninety");
one(a);
}
}
void hundred(int m)
{ int a=m%10,b,c;
b=a%10;
c=b%10;
one(c);
printf("Hundred");
d=b*10+a;
ten(d);
}
void main()
{ int a[3],i,n,m,c=0,r;
printf("\nEnter the no. in decimal:");
scanf("%d",&n);
m=n;c=0;
for(i=0;i<3;i++)
a[i]=0;
i=0;
do
{ r=n%10;
n%=10;
a[i]=r;
c++;
}while(n!=0);
if(c==1)
one(m);
else if(c==2)
ten(m);
else
hundred(m);
getch();
}
Just tried to give u an idea.May not be just perfect.

Answer 3

Use For..Next of Do..Loop function. For example,

*create a listbox named "List1".

*create a commandbutton then double click the button and copy-paste the code below.

Dim theIndex as Integer

For theIndex=0 to 299

List1.AddItem theIndex

Next

*run(f5) and click the button.

Answer 4

here it is

http://www.fileden.com/files/2008/9/1/2076797/randomgen0to999.txt