Write a program for a matchstick game being played between the computer and a user What if your program should ensure that the computer always wins using c plus plus?

Answer 1

The following example demonstrates a simple implementation using 15 matches where you take turns removing 1, 2 or 3 matches. The player who removes the last match loses.

In order to ensure the computer always wins, the computer must always play first. In the example, the player always starts but unless the player knows the secret, the computer will always win.

#include<iostream>

#include<conio.h>

unsigned ask(unsigned max=3)

{

int choice = 0;

do

{

choice = getch() - '0';

if (choice<0 choice>max)

choice=0;

else

{

std::cout<<choice<<'\n'<<std::endl;

break;

}

} while (!choice);

return ((unsigned)choice);

}

bool yn()

{

int choice = 0;

bool result = false;

while(1)

{

choice = getch();

if (choice=='y' choice=='Y')

{

result = true;

break;

}

if (choice=='n' choice=='N')

{

result = false;

break;

}

}

std::cout<<(char)choice<<'\n'<<std::endl;

return (result);

}

int main()

{

unsigned start = 15;

unsigned matches = start;

bool player = true; // set to false so computer always starts

unsigned take = 0;

while (1)

{

std::cout<<"There "<<(matches==1?"is":"are")<<" "<<matches<<" match"<<(matches==1?"":"es")<<" remaining.\n"<<std::endl;

if( matches <= 1 )

{

if ((player && matches == 1) (!player && !matches))

std::cout<<"You lose!\n"<<std::endl;

else

std::cout<<"You win!\n"<<std::endl;

std::cout<<"Would you like to play again? ";

if (!yn())

break;

else

{

matches = start;

continue;

}

}

if( player ) // player's turn

{

std::cout<<"Would you like to take 1";

if( matches>2 )

{

std::cout<<", 2 or 3 matches? ";

take = ask( 3 );

}

else

{

std::cout<<"or 2 matches? ";

take = ask( 2 );

}

}

else // computer's turn

{

take = (matches-1)%4;

if( !take )

take = rand()%3+1;

std::cout<<"I will take "<<take<<" matches.\n"<<std::endl;

}

matches -= take;

player = !player; // toggle player

}

}