Write a program that accepts two numbers a and b and checks whether or not a is divisible by b?

Answer 1

#include<stdio.h>

#include<conio.h>

#include<string.h>

int main (void) {

char arry[100];

int i,count=0;

float a,b;

printf("Enter a 2 Number ");

scanf("%d %d",&a,&b);

if(a%b == 0){printf("its divisible");} else {printf("its not divisible"); }

getch();

return 1;

}

Answer 2

There are many ways to do it.

• You could create a loop that subtracts the second from the first and stops when the first is no longer positive. If the first ever becomes zero, it's a multiple.
• You could divide the first with the second, multiply back the quotient with the second and compare with the first. If they are equal, it's a multiple.
• The easiest way is most likely the use of modulo operator to check the remainder after division. if(A%B == 0) printf("equal"); :)

Answer 3

#include

int main()

{

int m, n;

printf("Enter the values for M and N\n");

scanf("%d %d", &m, &n);

if (m / n!=1)

printf("divisible\n");

else

printf("not divisible\n");

}