Enter how many elements you want to enter: 4
Enter the array elements:
10
20
30
40
Enter the location, where you want to delete: 3
Deleted value : 30
The new element list: 10 20 40
/*
Removes the idx'th element from "list", an array of integers.
-- not tested --
Note that this routine assumes that the last element in the array has a null value.
*/
void dropElement(int *list, int idx){ int n;
for(n = 0; n < idx && list[n] != null; n++);
for(;list[n] != null; n++){list[n] = list[n + 1];}
}
You cannot delete from an array.
If you are using an array : sort using qsort() then take middle element.
int findMax(int *array) { int max = array[0]; for(int i = 1; i < array.length(); i++) { if(array[i] > max) max = array[i] } return max; }
To detect the duplicate, you will have to write a nested loop that compares each element with all the previous elements.To actually delete the duplicate, once you find it, you have to move over all the elements after the duplicate. If the order of the elements doesn't matter, it is faster to just move the LAST array element, overwriting the duplicate element. Use a variable to keep track how many elements of the array are "usable". For example, if your array had 10 elements, and you delete 1, the array size will still be 10... but (after moving the elements over) only 9 of those elements have useful information.
Usually one element at a time. If you want to process all elements of an array, you write a loop.Usually one element at a time. If you want to process all elements of an array, you write a loop.Usually one element at a time. If you want to process all elements of an array, you write a loop.Usually one element at a time. If you want to process all elements of an array, you write a loop.
// Assuming you dynamically allocated this array using "new"... delete array[arraysize - 1]; arraysize--;
You cannot delete elements from an array. But you can move the elements: if (del_index < no_of_elements-1) { memmove (&array [del_index], &array [del_index+1], sizeof (array [0]) * (no_of_elements - del_index - 1)); } --no_of_elements;
You cannot delete from an array.
Set it to null
If you are using an array : sort using qsort() then take middle element.
int findMax(int *array) { int max = array[0]; for(int i = 1; i < array.length(); i++) { if(array[i] > max) max = array[i] } return max; }
#include <stdio.h> #include <conio.h> #define size 10 void main() { int a[size],del,j,i; clrscr(); for(i=0;i<size;i++) {j=i+1; printf(" Enter the %d element of array",j); scanf("%d",&a[i]);} printf(" Enter the element to be deleted"); scanf("%d",&del); del--; for(i=del;i<size-1;i++) a[i]=a[i+1]; a[size-1]=0; printf(" Element has been deleted"); printf(" Array now is..... "); for(i=0;i<size;i++) printf("%d ",a[i]); getch(); }
Usually one element at a time. If you want to process all elements of an array, you write a loop.Usually one element at a time. If you want to process all elements of an array, you write a loop.Usually one element at a time. If you want to process all elements of an array, you write a loop.Usually one element at a time. If you want to process all elements of an array, you write a loop.
To detect the duplicate, you will have to write a nested loop that compares each element with all the previous elements.To actually delete the duplicate, once you find it, you have to move over all the elements after the duplicate. If the order of the elements doesn't matter, it is faster to just move the LAST array element, overwriting the duplicate element. Use a variable to keep track how many elements of the array are "usable". For example, if your array had 10 elements, and you delete 1, the array size will still be 10... but (after moving the elements over) only 9 of those elements have useful information.
The simplest way is probably to read the numbers into an array and then prints each element of the array starting at the last one and moving backwards.
/* using ellipses (...) to indicate tabs for clarity */ double largest (double *array, int M, int N) { ... int i, j; ... double *element; ... double answer = array[0][0]; ... for (i=0; i<M; i++) { ... ... for (j=0; j<N; j++) { ... ... ... element = array + i*M + j; ... ... ... if (*element > answer) answer = *element; ... ... } ... } ... return answer; }
== Java does not allow reference to memory locations. == In C: for (i=0; i<n; ++i) printf ("a[%d] is at %p\n", i, &a[i]);