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Assuming the numbers are integers, and they are stored in an array called myArray. The following has not been tested, but gives the general idea: int max; max = myArray[0]; for (int i = 1; i < myArray.length(); i++) } if (myArray[i] > max) max = myArray[i]; System.out.println(max); }
Assuming the numbers are integers, and they are stored in an array called myArray. The following has not been tested, but gives the general idea: int max; max = myArray[0]; for (int i = 1; i < myArray.length(); i++) } if (myArray[i] > max) max = myArray[i]; System.out.println(max); }
Assuming the numbers are integers, and they are stored in an array called myArray. The following has not been tested, but gives the general idea: int max; max = myArray[0]; for (int i = 1; i < myArray.length(); i++) } if (myArray[i] > max) max = myArray[i]; System.out.println(max); }
Assuming the numbers are integers, and they are stored in an array called myArray. The following has not been tested, but gives the general idea: int max; max = myArray[0]; for (int i = 1; i < myArray.length(); i++) } if (myArray[i] > max) max = myArray[i]; System.out.println(max); }
Wiki User
∙ 14y ago
Wiki User
∙ 14y agoAssuming the numbers are integers, and they are stored in an array called myArray. The following has not been tested, but gives the general idea: int max; max = myArray[0]; for (int i = 1; i < myArray.length(); i++) } if (myArray[i] > max) max = myArray[i]; System.out.println(max); }
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