Write a program to implement the various operations on string such as length of string concatenation reverse of a string copy of a string to another in c anguage?

Answer 1

These should work, if used correctly.

// stores srcL + srcR into dest

// NOTE: dest must be at least as large as srcL + srcR

void strConcat(const char* srcL, const char* srcR, char* dest) {

const int lengthL = strLength(srcL);

const int lengthR = strLength(srcR);

// copy srcL into front of dest

int i;

for(i = 0; i < lengthL; ++i) {

dest[i] = srcL[i];

}

// copy srcR into the rest of dest

for(i = 0; i < lengthR; ++i) {

dest[lengthL + i] = srcR[i];

}

dest[lengthL + i] = '\0';

}

// copies characters from src to dest

// NOTE: dest must be at least as large as src

void strCopy(const char* src, char* dest) {

const int length = strLength(src);

// copy

int i;

for(i = 0; i < length; ++i) {

dest[i] = src[i];

}

}

// reverses str and puts the result in buff

// NOTE: buff must be at least as large as str

void strReverse(const char* str, char* buff) {

const int length = strLength(str);

// special case for zero-length strings

if( length == 0 ) {

return;

}

// reversify

int i;

for(i = 0; i < length; ++i) {

buff[i] = str[length - i - 1];

}

buff[i] = '\0';

}

// returns the number of characters in str

int strLength(const char* str) {

int length = 0;

// take advantage of the fact that all strings MUST end in a null character

while( str[length] != '\0' ) {

++length;

}

return length;

}