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Unless someone is willing to write an entire program for you (which I would, but I don't have the patience to learn an entire new programming language to answer one question) I think the best you'll get is this:
- To get user input: var = raw_input("Enter something: ")
- To separate a number into its single digits: var = "your number"
var2 = list(var) var2 will have what seems to be an array of each number.
- foreach loops in Python are just: for "item" invar2: # do something with item such as cube it and add it to another variable set aside for the overall value. Or cube it and subtract it from the original and at the end check if what used to be the original is now zero.
- Lastly, if it's in quotes you can change it.
Another way to do it (which would be easier but would probably take slightly longer and has a limit of number 10 digits or less) would be to check to see if the number is in the list in the related link.
I've been curious about Python before so if I end up getting to the point that I can write a simple program in it I'll add it to the related links.
Wiki User
∙ 14y ago
Wiki User
∙ 12y agodef isArmstrongNumber(num):
factor = len(str(num))
res = 0
for digit in str(num):
res = res + (int(digit)**factor)
if (num == res):
return True
else:
return False
for i in range(1000):
if isArmstrongNumber(i):
print i,
#Result:
0 1 2 3 4 5 6 7 8 9 153 370 371 407
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import java.io.*; public class Jerry { public static void main(String as[]) throws IOException { int k=Integer.parseInt(as[0]); int n=k; int d=0,s=0; while(n>0) { d=n%10; s=s+(d*d*d); n=n/10; } if(k==s) System.out.println("Armstrong number"); else System.out.println("not Armstrong number"); } }
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