Cobalt electron configuration is [Ar]3d7.4s2.
Nitrogen electron configuration is [He]2s2.2p3.
Absorb appx 12.1eV (electron Volts) of energy. Energy of 1st level is -13.6eVEnergy of 3rd level is -1.5eV Hence, energy required = 13.6 - 1.5 = 12.1 eV
The charge on one electron is 1.6 x 10-19 C.610 N per C means 9.76 x 10-17 N on 1.6 x 10-19 C.
We can calculate using these below given formulas:-Energy of n(th) shell = -2.18*10^(-18)*(Z/n)^2 Joules per atom, orEnergy of n(th) shell = -13.6*(Z/n)^2 Electron volt per atom, orEnergy of n(th) shell = -1.312*(Z/n)^2 KiloJoules per molewhere n is your number of orbit and Z is it's atomic number
tablet hardness units Kp and N has co-relation as below. Kp (kiloponds) = 10 N (Newton)
n is the principal quantum number and represents the energy level or electron shell in which an electron resides. For example - Say you have an Oxygen atom, which has 8 electrons. It's electron configuration is 1s2 2s2 2p4. The 2 in 2p4 is the principle quantum number, n. The s is another term dealing with angular momentum and the 4 is the number of electrons.
The valance electron configuration is the same in each at ns1 where n = the period number.
The valance electron configuration is the same in each at ns1 where n = the period number.
group 3- (n-1)d1 ns2. Group 12 (n-1)d10 ns2, groups 4-11 do not necessarily have identical outer electron configurations. Where n represents your period that you are in.
Every alkali metal has only one electron in the outermost energy level. They give it away to form monopositive ions which have stable electron configurations ending with ns2 np6 (where n is a counting number between 2 and 7 inclusive).
Energy
decreased
The halogens are is group VII (17), and thus they all have 7 valence electrons. These will be located in different energy levels for the different halogens, but since they are all also p-block elements, they will all have ns^2 np^5 electron configurations, where n is the period number. Examples: Cl will be [Ne] 3s^2 3p^5 and Br will be [Ar] [Ar] 4s2 3d10 4p5 (note the inclusion of the d-block electrons for Br).
Group 13 (B, AL, Ga, In, Tl) all have (n)s2 (n)p1 configurations, in wch (n) has a value of 2, 3, 4, 5. Hence they have 3 valence electrons.
It is called a(n) Electron.
Shorter wavelength = more energy. The farther the electron falls, the more energy that will be emitted.
2n2 where n is the electron level
N o no