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Yes i got married in Reno nv at 200now i live at Mexico.i need to find where can i look for divorce records?
Wiki User
∙ 15y ago
You should be able to obtain a copy of the divorce papers from the court where you received your divorce.
Wiki User
∙ 15y ago
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What does cclxxv mean?
i think something is wrong...(c)means 100 (l) means 1 and(x)means 10 and (v)means 5 if we read (cc) read it 200 because (c) is equal to 100 and u have two (c) its like 100 + 100 =200so now we have 200now lets go to (l) = 1so now we have 1lets go to (x)=10 and u have two x (xx)=20and (v)=5.....if we add all its like...200+1+20+5=226 but the equation is wrong...when we read the (lX) we dont read it 11 because 11 is like this=(Xl)so x is 10 and l is 1(X) - (l) = 9now lets continue...200+9+10 because you have another (X)200+9=10+5=224im not sure of my answer but i think my equation is correct..;)Improved Answer:-cclxxv is the same as CCLXXV and they represent 275 in Roman numerals
What is the quote of line 194-201 of Beowulf?
Here is a translation of lines 194-201 of Beowulf in Old English: "Beowulf maðelode, beotwordum spræc, ecne gemyndig eþelweard sīnne: 'Ic þæt hogode to geþoligenne, glædnian in garrum, gif mec god þohte þæt ic mid Hroþgare maegan minne moste geþeon.'" This translates to: "Beowulf spoke, made a formal boast in words, remembered his folk right: 'I resolved to fulfill it, to gladden your heart, if God should grant me that I might allow my kinsman with Hrothgar.'"
If a ship travels 200 km to the south and then 400 km to the west what would be the ship's displacement from its starting point?
If it is travelling due south and due west, then to find the displacement, we can use pythagoras' thereom because it would be a right-angled triangle.pythagoras' thereom states that a^2+b^2=c^2If we say that a = 200km, and b = 400km, then c^2 = 200^2+400^2so c = (200^2+400^2)^1/2*note that the squareroot of something is also known as being to the power of 1/2so if we equate that,c = 447.214km displacement from its starting point.Since it is the displacement we are finding, we also need a direction.To find the bearing of the point c from the starting point, because it is a right-angled triangle, we can use Tan(theta) = O/AWe know that the opposite side length (O) is 400km, and the adjacent side length (A) is 200km.So Tan(theta) = 400/200Now we inverse Tan it to get the angle theta.Theta = 63 degrees 26 minutes or 63.435 degreesNow, because it is bearings, we cannot simply just write it as 63.435 degrees, it must have a direction of North, East, South or West.Seeing that it is in the 3rd quadrant, it is in the South-West quadrant, and so the angle is South 63 degrees 26 minutes West OR we can write it in true bearings form, and knowing that each quadrant is 90 degrees, we add the first and second quadrant, with the value we get inside our 3rd quadrant, which gives us 63"26' + 90 + 90 = 243 degrees 26 minutes True.Finally, because this is a worded question, write a worded answer for it.The displacement of the ship is 447.214km on a bearing of South 63 degrees 26 minutes West from the starting point.
