you now need an amp that will power them both and a wireing kit and a box or 2 to put them in and a place to put them.
You would need Four DC Audio 7.5k for 15 Digital Designs 9918Z 18 subwoofers.
Yes, that is correct a punch75hd can push 2 15 inch subwoofers
No, if you read online you can do it yourself.
Yes, they are just as easy as any other subwoofer.
One of the most popular subwoofers that are high quality are Pioneers. They have been making audio equipment for a long time and their products tend to last for years. Another good product is JBL.
Yes. Most head units only put out about 15-20 watts RMS, you need more than that to properly power a subwoofer. Ignore peak ratings, only use RMS ratings to match everything together.
yes, you can do it but you have to have a custome box built and mabe a shallow mount subwoffer.
Subwoofers are loud speakers used for the purpose of reproducing low frequencies (10Hz - 150Hz). They use large magnets to move a firm cone in order to produce the frequencies. A current is passed through the magnet causing the cone to move producing bass. Subwoofers in cars and in home theatre systems use amplifiers to boost electrical power to provide large amounts of the deep notes. I have 2 15" Kicker CVR subwoofers, custom box, 1200W RMS Audison Amplifier. Hope that helps
Yes! The "Soundstream XXX-15" puts out 8500 watts of high performance power. These are XXX-Series competition quality subwoofers.
You can but it probably won't hit that hard. I don't know the subs rms but if there 15s should be atleast 800 to 1000 rms . Get 1 Audiopipe 1500 monoblock . That will push them
If you take 208.56 and divide it by 100 you can find 1%, which is 2.0856 if you now multiply it by 15 you can find 15%, which is 31.284. Now all you need to do is subtract 31.284 (15%) from 208.56, which gives you 177.276
1 2/3 + 4 7/15... First - covert both fractions to the same denominator... 2/3 = 10/15 the 7/15 fraction doesn't need converting. Now you have 10+7 which of course is 17/15. 17/15 is 1 2/15 - now add the whole numbers (1+4) from the original problem, and your final answer is 6 2/15