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Ohm's law states that voltage is resistance times current. In a resistor circuit, knowing two of voltage, current, or resistance, you can calculate the third.
Actually, this applies to any circuit, be it resistor, capacitor, or inductor. Ohm's law still applies - it just gets more complex when the phase angle of current is not the same as the phase angle of voltage.
What else can I help you with?
Can you provide some Ohm's Law practice questions for me to work on?
Here are some practice questions based on Ohm's Law: If a resistor has a resistance of 10 ohms and a current of 2 amperes flowing through it, what is the voltage across the resistor? A circuit has a voltage of 12 volts applied across a resistor with a resistance of 4 ohms. What is the current flowing through the resistor? If a circuit has a current of 0.5 amperes flowing through a resistor with a resistance of 8 ohms, what is the voltage across the resistor? These questions will help you practice applying Ohm's Law to calculate voltage, current, and resistance in electrical circuits.
How do you find resistance when you have current and resistance total?
If you are looking for the resistance of each resistor in either a series circuit or a parallel circuit you must measure the current I and the voltage V for each resistor. Then calculate its resistance using Ohms Law R = V / I where I = current (Amps), V = voltage (Volts) and R= resistance (Ohms).
If there is a potential difference of 12 V across a resistor with 0.25 A current in it the resistance if the resistor is?
Resistance (Ohms) = Potential Difference (Volts) / Current (Amps) So, 12/0.25 = 48 Ohms.
An electric DC circuit is attached to a 12 volt battery and has a 3 ohm resistor in it find the current flowing through the circuit?
If the 3-ohm resistor is the ONLY thing in the circuit, then the current flowing through it is (12 volts)/(3 ohms) = 4 amperes. If there are other things in the circuit besides the resistor, then the current depends on all of them.
Why does the total circuit decrease when more devices are added to a parallel circuit?
This is a direct consequence of Ohms Law. Since each new resistor connected in parallel will allow more current to flow, the resistance of the circuit must be lower. R = E/I. Since I (current) has increased, and the voltage E is still the same, it follows that R (resistance) must be smaller. That's the way Ohms Law works.
When Resister is 120 volts and the current through the resister is 0.5 Amps determine the value of the resistor in ohms?
Using Ohms Law, the answer is 120/0.5 = 240 Ohms.
What is the difference between a normal resistor and a bleeder resistor?
A resistor is a resistor. Plain and simple. By Ohm's Law, resistance in ohms is voltage in volts divided by current in amperes. The difference lies in application, not in the resistor itself. A normal resistor will introduce a voltage drop or current that makes some effect in the circuit, based on some design criteria. A bleeder resistor, on the other hand does not really affect the circuit - it is only there to "bleed off", or discharge, capacitors when the power is turned off. Consequently, a bleeder resistor will typically have a higher resistance than a normal resistor but, again, the issue is circuit design, not the resistor itself.
In a series circuit each device that is added to the circuit decreases the what?
Depends on the device. If it is a resistor and you have a fixed voltage then the circuit will obey Ohms law. Voltage = Current x Resistance. So if R increases by adding more resistors in series and the voltage is constant, the current will decrease.
What is the current flowing through the first device of a circuit when the first device has a resistance of 12 ohms and the 2nd device has a resistance of 4 ohms circuit voltage is 40 volts.?
You describe a series circuit. This answer is for a series circuit. The total impedance is 16 Ohms, 12 + 4. The current by Ohm's Law (Amps = Volts / Ohms) is 40 / 16, or 2.5 Amps. Kirchoff's Current Law says that the current at every point in a series circuit is the same, so the current flowing into the 1st device, the 12 Ohm resistor, is 2.5 Amps.
If the current running through a wire is 1.2 amperes and it passed through a resistor of 7.5 Ohms what is the voltage of the system?
9V by using ohms law
What is the measured voltage across the 680 ohms resistor?
No one is going to be able to tell you that. You are looking for the measured voltage, so go and measure it. In any case, if you were just looking for the voltage it will depend on the circuit current. You can work it out using ohms law (Voltage = Current * Resistance).
When a resistor is connected to a 25.0 V power supply the current through the resistor is 12.5 A.Calculate the resistance of a second resistor connected in series that reduces the current to 5.00 A.?
R2 = 3 ohms Explanation: For a circuit you can use ohms law where: V=I*R Where V is the voltage difference throughout the surface, I is the current, and R is the total resistance of the circuit. In your case you want to find the resistance so you have to change the formula to: R=V/I R of first circuit = 25volts/12.5amps = 2 ohms R of second circuit= 25 volts / 5 amps = 5 ohms The resistors here are connected in series which means that the resistance of the two can be added together. This gives you: Rtot= R1+R2 we found R of the first resistor by calculating the resistance in the first circuit. We also found Rtot which is the resistance in the second circuit, when you connect the two resistors together in series. Rtot=2 ohms+R2 5ohm=2ohms+R2 R2 = 3 ohms If the resistors where connected in parallel you cannot simply add the resistance. In that case: (1/Rtot)=(1/R1)+(1/R2) Hope that helps
