No one is going to be able to tell you that. You are looking for the measured voltage, so go and measure it. In any case, if you were just looking for the voltage it will depend on the circuit current. You can work it out using ohms law (Voltage = Current * Resistance).
Resistance is measured in ohms.
V = IR Voltage (V, measured in volts) = Current (I measured in amps) times Resistance (R, measured in Ohms) Is your current 3.13? I'm not sure what you wrote there, but just multiply your current times your resistance.
There is insufficient information in the question to answer it. You need to provide either the voltage across the resistor, or the power dissipated by the resistor. please restate the question.
V=IR by ohms law. Voltage across the resistor is the product of current flowing and resistance of the conductor at constant temperature.
In order to determine what size of resistor is required to operate an LED from a 9V battery, first start by knowing the current and voltage required for the LED. That information is available in the LED's specifications. For discussion purposes, lets assume a typical LED at 2.5V and 50mW. The translates to a forward current of 20mA. Build a simple series circuit containing a 9V battery, a resistor of an as yet unknown value, and the LED. By Kirchoff's current law, the current in the LED is the same as the current in the resistor, which is also the same as the current in the battery. This is 20ma. By Kirchoff's voltage law, the voltage across the LED plus the voltage across the resistor equals the voltage across the battery. This is 6.5V. (9 - 2.5) By Ohm's law, resistance is voltage divided by current, so the resistor is 6.5 / 0.02, or 325 Ohms. The nearest standard value to that is 330 Ohms. Cross check the power through the resistor. Power is voltage times current, or 6.5V times 0.02A, or 0.13W. A half watt resistor is more than adequate for this job.
A resistor's resistance is measured in ohms. The higher the resistance the less current will flow with a constant voltage applied across the resistor. In terms of Ohm's Law Voltage = Current x Resistance.
Here are some practice questions based on Ohm's Law: If a resistor has a resistance of 10 ohms and a current of 2 amperes flowing through it, what is the voltage across the resistor? A circuit has a voltage of 12 volts applied across a resistor with a resistance of 4 ohms. What is the current flowing through the resistor? If a circuit has a current of 0.5 amperes flowing through a resistor with a resistance of 8 ohms, what is the voltage across the resistor? These questions will help you practice applying Ohm's Law to calculate voltage, current, and resistance in electrical circuits.
Resistance is measured in ohms.
V = IR Voltage (V, measured in volts) = Current (I measured in amps) times Resistance (R, measured in Ohms) Is your current 3.13? I'm not sure what you wrote there, but just multiply your current times your resistance.
Voltage is not measured in ohms. It is measured in volts.
No, resistors are measured in ohms, not amps. Ohms represent the resistance offered by the resistor to the flow of current, whereas amps (amperes) represent the measure of current flowing through a circuit.
There is insufficient information in the question to answer it. You need to provide either the voltage across the resistor, or the power dissipated by the resistor. please restate the question.
Using Ohm's Law (V = I * R), we can rearrange the formula to solve for the resistance. For the first scenario: 1.0 V = 3.0 A * R R = 1.0 V / 3.0 A = 0.33 ohms Now with a voltage drop of 9.0 V: 9.0 V = I * 0.33 ohms I = 9.0 V / 0.33 ohms = 27.27 A
V=IR by ohms law. Voltage across the resistor is the product of current flowing and resistance of the conductor at constant temperature.
V = (I) x (R) = 2 x 12 = 24 volts
In order to determine what size of resistor is required to operate an LED from a 9V battery, first start by knowing the current and voltage required for the LED. That information is available in the LED's specifications. For discussion purposes, lets assume a typical LED at 2.5V and 50mW. The translates to a forward current of 20mA. Build a simple series circuit containing a 9V battery, a resistor of an as yet unknown value, and the LED. By Kirchoff's current law, the current in the LED is the same as the current in the resistor, which is also the same as the current in the battery. This is 20ma. By Kirchoff's voltage law, the voltage across the LED plus the voltage across the resistor equals the voltage across the battery. This is 6.5V. (9 - 2.5) By Ohm's law, resistance is voltage divided by current, so the resistor is 6.5 / 0.02, or 325 Ohms. The nearest standard value to that is 330 Ohms. Cross check the power through the resistor. Power is voltage times current, or 6.5V times 0.02A, or 0.13W. A half watt resistor is more than adequate for this job.
The ohm. It is how much resistance a component or part of a circuit has to the flow of electrical charge when a voltage is induced across it.