Find the block heater and look for the nameplate on it. It will be in watts. Use the following equation to find the amperage that it draws. Amps = Watts/Volts. The voltage to use for the truck will be 12 volts.
To answer this question the wattage of the block heater must be stated. Amps = Watts/Volts.
It uses 1150 watts, or 10 amps.
A typical 120 volt diesel engine block heater can pull around 1000-1500 watts, which would translate to approximately 8-12.5 amps. It's important to check the specifications of the specific block heater you are using to get an accurate measurement.
Watts is the amount of power the heater has and amps would be the draw- if it is a 120 volt heater than the amps would be 12.5 amps and it is instantaneous
The heater should have a wattage rating (very few list amps). Calculate the amps using the wattage and voltage. Amps = Watts/Volts(480).
To calculate the amperage for a 240-volt, 1500-watt electric baseboard heater, you can use the formula: Amps = Watts / Volts. For this heater, it would be 1500 watts / 240 volts, which equals 6.25 amps. Therefore, the heater uses approximately 6.25 amps.
Watts = Amps x Volts for a resistive load like a water heater.
To calculate the amperage for a 10kW heater on a 3-phase 220V system, use the formula: Amps = (kW x 1000) / (√3 x Volts). So, Amps = (10 x 1000) / (√3 x 220) = 26.18 amps per phase. Therefore, the total current drawn by the heater is 26.18 amps per phase multiplied by 3, which equals approximately 78.54 amps.
46 amps
45-50 amps. But your overcurrent protection and wire must be designed for 125% of load so the max overcurrent protection is 55 amps or 60
To determine the amperage draw of a 5200 BTU heater, you can use the formula: Amps = BTUs / (Voltage x Efficiency). For example, if the heater operates at 120 volts and has an efficiency of about 100%, it would pull approximately 43.3 amps (5200 BTU / 120 volts). However, many small heaters operate at lower voltages (like 120V), so it's essential to check the specific heater's specifications for accurate amperage.
The formula you are looking for is I = W/E.