The mass is 55.85 and you can find the mass of iron on a Periodic Table.
The molar mass of iron is 55,845 g.Moles of iron = mass of iron/55,845
To find the number of moles in 1.25 grams of iron nitrate, we need to know its molar mass. Iron nitrate has a molar mass of approximately 404.0 g/mol. By dividing the mass by the molar mass, we find that 1.25 grams of iron nitrate is roughly 0.0031 moles.
To find the mass of reacting sulfur, we can use the law of conservation of mass, which states that the mass of the reactants equals the mass of the products. Here, the mass of iron sulfide produced (8.79 g) is the sum of the mass of iron (5.58 g) and the mass of sulfur. Thus, the mass of sulfur can be calculated as: Mass of sulfur = Mass of iron sulfide - Mass of iron Mass of sulfur = 8.79 g - 5.58 g = 3.21 g. Therefore, the mass of reacting sulfur is 3.21 g.
The molar mass of iron is 55.85 g/mol. To find the mass of 2.38 moles of iron, you would multiply the number of moles by the molar mass: 2.38 mol * 55.85 g/mol = 133.03 g. Therefore, the mass of 2.38 moles of iron is 133.03 grams.
To find the theoretical mass of iron in one serving of cereal, you first need to check the nutritional label for the iron content per serving, usually listed in milligrams (mg). Then, convert this amount to grams by dividing by 1,000, as there are 1,000 mg in a gram. If the iron is in a compound form (like ferrous sulfate), you may need to calculate the specific mass of iron based on the molar mass of the compound and the proportion of iron in it. Finally, use this information to express the theoretical mass of iron in grams.
It is g units [of mass] per cubic metre.
To calculate the mass of iron in chalcopyrite (CuFeS2), we need to find the atomic mass of iron and the chemical formula weight of chalcopyrite. Iron has an atomic mass of 55.85 g/mol, and the formula weight of chalcopyrite is 183.54 g/mol. The mass percentage of iron in chalcopyrite is calculated by (55.85 / 183.54) x 100 = 30.45%. Therefore, the mass of iron in 86.6 grams of chalcopyrite can be found by multiplying 86.6 g by 0.3045 to get 26.34 grams of iron.
A single iron atom weighs 55.845 atomic mass units.The weight of a quantity of pure iron will vary depending on the volume and gravitational acceleration. The mass of iron will also vary depending on the given volume. Given the density at room temperature, 7.874 g·cm−3 and the volume of iron, you can find the mass by multiply the density and the volume. To find the weight of an object, you would need to multiply its mass by the local gravitational acceleration.
To calculate the amount of iron in Fe2S3, first find the molar mass of Fe2S3: Iron (Fe) has a molar mass of 55.85 g/mol and sulfur (S) has a molar mass of 32.06 g/mol. So, the molar mass of Fe2S3 is 2(55.85) + 3(32.06) = 222.92 g/mol. Next, divide the molar mass of iron by the molar mass of Fe2S3 and multiply by the given mass of Fe2S3 to find the grams of iron: (2 * 55.85 g/mol / 222.92 g/mol) * 34 g = 8.53 g of iron in 34 g of Fe2S3.
To calculate the mass of iron (II) sulfate (FeSO4), you would first find the atomic mass of each element (iron, sulfur, and oxygen) using the periodic table. Then, add the atomic masses of each element (Fe + S + 4O) to find the molar mass of FeSO4, which is approximately 151.91 g/mol. Finally, you can then calculate the mass of FeSO4 by multiplying the molar mass by the number of moles.
To find the mass of iron in CuFeS2, we first calculate the molar mass of CuFeS2: Cu (copper) has a molar mass of 63.5 g/mol, Fe (iron) has a molar mass of 55.8 g/mol, and S (sulfur) has a molar mass of 32 g/mol. Adding these together gives a molar mass of 151.3 g/mol for CuFeS2. Next, calculate the mass percentage of iron in CuFeS2 by dividing the molar mass of iron by the molar mass of CuFeS2 and multiplying by 100. The percentage of iron is approximately 37%, so in 86.6 grams of CuFeS2, the mass of iron would be 0.37 * 86.6 grams = 32 grams.
The atomic mass of iron is approximately 55.85 atomic mass units.