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To find the mass of iron in CuFeS2, we first calculate the molar mass of CuFeS2: Cu (copper) has a molar mass of 63.5 g/mol, Fe (iron) has a molar mass of 55.8 g/mol, and S (sulfur) has a molar mass of 32 g/mol. Adding these together gives a molar mass of 151.3 g/mol for CuFeS2. Next, calculate the mass percentage of iron in CuFeS2 by dividing the molar mass of iron by the molar mass of CuFeS2 and multiplying by 100. The percentage of iron is approximately 37%, so in 86.6 grams of CuFeS2, the mass of iron would be 0.37 * 86.6 grams = 32 grams.
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What mass of iron is contained in 86.6 grams of chalcopyrite?
To calculate the mass of iron in chalcopyrite (CuFeS2), we need to find the atomic mass of iron and the chemical formula weight of chalcopyrite. Iron has an atomic mass of 55.85 g/mol, and the formula weight of chalcopyrite is 183.54 g/mol. The mass percentage of iron in chalcopyrite is calculated by (55.85 / 183.54) x 100 = 30.45%. Therefore, the mass of iron in 86.6 grams of chalcopyrite can be found by multiplying 86.6 g by 0.3045 to get 26.34 grams of iron.
What mass of iron ore in kilograms will contain 15.64 grams of iron if the ore contains 0.257 iron by mass?
The mass of iron ore is 6,085 kg.
How much energy is contained in matter with a mass of 2 grams?
1.8e14 j
What is the mass in grams for 0.226 mole of Iron hydroxide?
It depends on whether it is iron (II) hydroxide or iron (III) hydroxide.
What information does the molar mass gives?
It is the sum of the atomic weights of atoms contained in the molecule, expressed in grams.
What mass of iron is contained in 86.6 grams of chalcopyrite?
To calculate the mass of iron in chalcopyrite (CuFeS2), we need to find the atomic mass of iron and the chemical formula weight of chalcopyrite. Iron has an atomic mass of 55.85 g/mol, and the formula weight of chalcopyrite is 183.54 g/mol. The mass percentage of iron in chalcopyrite is calculated by (55.85 / 183.54) x 100 = 30.45%. Therefore, the mass of iron in 86.6 grams of chalcopyrite can be found by multiplying 86.6 g by 0.3045 to get 26.34 grams of iron.
How many grams equal 3.95 moles of CuFeS2?
To find the grams of CuFeS2 in 3.95 moles, you need to know the molar mass of CuFeS2, which is approximately 183.5 g/mol. Therefore, 3.95 moles of CuFeS2 would be 3.95 moles * 183.5 g/mol ≈ 724.325 grams.
How many grams of iron are contained in 34 grams of fe2s3?
To calculate the amount of iron in Fe2S3, first find the molar mass of Fe2S3: Iron (Fe) has a molar mass of 55.85 g/mol and sulfur (S) has a molar mass of 32.06 g/mol. So, the molar mass of Fe2S3 is 2(55.85) + 3(32.06) = 222.92 g/mol. Next, divide the molar mass of iron by the molar mass of Fe2S3 and multiply by the given mass of Fe2S3 to find the grams of iron: (2 * 55.85 g/mol / 222.92 g/mol) * 34 g = 8.53 g of iron in 34 g of Fe2S3.
What mass of iron ore in kilograms will contain 15.64 grams of iron if the ore contains 0.257 iron by mass?
The mass of iron ore is 6,085 kg.
How many moles are in 1.5 grams of iron?
To find the number of moles in 1.5 grams of iron, you need to divide the mass of iron by its molar mass. The molar mass of iron is approximately 55.85 g/mol. So, 1.5 grams of iron is equal to 1.5 g / 55.85 g/mol = 0.027 moles of iron.
What is the mass of 4 moles of iron?
The molar mass of iron is approximately 55.85 g/mol. Thus, the mass of 4 moles of iron would be 4 moles * 55.85 g/mol = 223.4 grams.
How much energy is contained in matter with a mass of 2 grams?
1.8e14 j
How many moles in 1.25 grams of iron nitrate?
To find the number of moles in 1.25 grams of iron nitrate, we need to know its molar mass. Iron nitrate has a molar mass of approximately 404.0 g/mol. By dividing the mass by the molar mass, we find that 1.25 grams of iron nitrate is roughly 0.0031 moles.
What is the mass in grams of 1.40 mol of iron (III) sulfate'?
To find the mass of 1.40 mol of iron (III) sulfate (Fe2(SO4)3), you need to calculate the molar mass of the compound. Iron (III) sulfate has a molar mass of approximately 399.9 g/mol. Therefore, the mass of 1.40 mol of iron (III) sulfate would be 1.40 mol x 399.9 g/mol = 559.86 grams.
What is the mass in grams for 0.226 mole of Iron hydroxide?
It depends on whether it is iron (II) hydroxide or iron (III) hydroxide.
What does 7.4 moles of iron weigh in grams?
The molar mass of iron is 55.85 g/mol. To find the weight of 7.4 moles of iron, you would multiply the number of moles by the molar mass. Therefore, 7.4 moles of iron would weigh 7.4 moles * 55.85 g/mol = 411.49 grams.
How many grams of iron could be recovered from 75.89 g FeO?
To calculate the amount of iron that can be recovered from FeO, we need to consider the molar ratio between Fe and FeO. FeO consists of 1 iron atom and 1 oxygen atom. The molar mass of Fe is 55.85 g/mol, and the molar mass of FeO is 71.85 g/mol. By dividing the molar mass of Fe by the molar mass of FeO and multiplying by the given mass of FeO, we can determine the amount of iron that can be recovered.
