To multiply two matrices using pointers in C, you can create a function that takes pointers to the matrices and their dimensions as parameters. Use nested loops to iterate through the rows of the first matrix and the columns of the second matrix, calculating the dot product for each element in the resulting matrix. Store the results in a dynamically allocated array, ensuring to properly manage memory. Here's a brief code snippet to illustrate the concept:
void multiplyMatrices(int *A, int *B, int *C, int rowsA, int colsA, int colsB) {
for (int i = 0; i < rowsA; i++) {
for (int j = 0; j < colsB; j++) {
C[i * colsB + j] = 0; // Initialize the result element
for (int k = 0; k < colsA; k++) {
C[i * colsB + j] += A[i * colsA + k] * B[k * colsB + j];
}
}
}
}
You do not multiply pointers. If you want to multiply the values that they point to you must dereference them, usually with a *
constant pointer and character pointer
By dereferencing the pointer variable. This can be achieved in two ways: typedef struct s { int i; float f; }; void f (struct s* p) { int x = p->i; /* using pointer to member operator */ float y = (*p).f; /* using dereference operator */ } The two methods are functionally equivalent.
2x2x2x3x3=72
If you are standing behind the three point line, the arc going around the hoop, it is a three-pointer. Any other shot is a two-pointer.
A double pointer has two basic meanings. One is ofa pointer to a pointer, where changing the value ofdouble pointer will result in the original pointer being changed. Another is that of a two-dimentional array, such as a matrix, or a list of char* (e.g. in main when you use argv).
yes
You multiply the number together - using a calculator if needed.
if (*&a > *&b) *&max = *&a; else *&max = *&b;
no
two heanded arrow
add the number how many times it says