The greater the distance, the longer is the orbital period and the slower the velocity.
"Kepler's Laws of Planetary Motion" contain mathematical details.
Further explanation is given by the work of Isaac newton and his theory of
gravitation.
For example, one version of Kepler's 3rd law is :
The square of the orbital period (in Earth years) equals the cube of the average distance from the Sun (in Astronomical Units).
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The second half of the question can be answered from the above formula.
For example, a planet at four times the distance of Earth from the Sun would go round the Sun in eight years.
The length of that orbit would be (almost exactly) four times as far as Earth's.
So, the planet would travel at half the speed of Earth.
In this example, and also generally, the orbital speed is inversely proportional to the square root of the average distance from the Sun.
The approximate orbital period of an object at a distance of 65 AU from the sun would be around 177 years. This corresponds to Kepler's third law of planetary motion, which relates the orbital period of a planet to its distance from the sun.
Kepler's third law of planetary motion states that the square of a planet's orbital period is directly proportional to the cube of its average distance from the sun. This relationship allows us to predict the orbital period of a planet based on its distance from the sun, and vice versa.
Yes, the square of the orbital period of a planet is proportional to the cube of the average distance of the planet from the Sun. This relationship is known as Kepler's Third Law of Planetary Motion. It describes the mathematical relationship between a planet's orbital period and its average distance from the Sun.
Because Venus has less distance to travel than the Earth and is travelling faster. With an orbital speed of 35.02 km/s and an orbital period of 224.70069 days gives an orbital distance of 679,883,169.35km The Earth has an orbital speed of 29.78 km/s (Slower than Venus) and an orbital period of 365.256 days gives an orbital distance of 939,800,765.95km
The orbital period of a planet can be calculated using Kepler's third law: P^2 = a^3 where P is the orbital period in years and a is the semi-major axis in astronomical units. For a planet with an average distance of 10 au, its orbital period would be approximately 31.6 years.
A planet's orbital period is related to its distance from the Sun by Kepler's third law, which states that the square of the orbital period is proportional to the cube of the semi-major axis of the orbit. For an orbital period of 3 million years, the planet would need to be located at a distance of approximately 367 AU from the Sun.
The distance of a planet from the sun affects its orbital period. Generally, the farther a planet is from the sun, the longer its orbital period will be. This relationship is described by Kepler's third law of planetary motion, which states that the square of a planet's orbital period is directly proportional to the cube of its average distance from the sun.
The period of a planet's revolution can be used to calculate its orbital radius or distance from the sun using Kepler's third law of planetary motion. It can also be used to determine the planet's orbital speed or velocity if its mass is known. Additionally, the period of revolution helps in predicting future positions of the planet along its orbit.
The approximate orbital period of an object at a distance of 65 AU from the sun would be around 177 years. This corresponds to Kepler's third law of planetary motion, which relates the orbital period of a planet to its distance from the sun.
Distance Traveled is directly proportional to velocity. This is because velocity is the change in position over a period of time. The greater the velocity, the greater the distance traveled. For you calculus junkies, integrate velocity to get displacement.
Kepler's third law of planetary motion states that the square of a planet's orbital period is directly proportional to the cube of its average distance from the sun. This relationship allows us to predict the orbital period of a planet based on its distance from the sun, and vice versa.
You can calculate this with Kepler's Third Law. "The square of the orbital period of a planet is directly proportional to the cube of the semi-major axis of its orbit." This is valid for other orbiting objects; in this case you can replace "planet" with "satellite". Just assume, for simplicity, that the satellite orbits Earth in a circular orbit - in this case, the "semi-major axis" is equal to the distance from Earth's center. For your calculations, remember also that if the radius is doubled, the total distance the satellite travels is also doubled.
Temperature and orbital period.
Velocity is a measure of how fast an object is moving in a specific direction. It is calculated by dividing the distance traveled by the time it took to travel that distance. The formula for velocity is velocity distance/time.
Yes, the square of the orbital period of a planet is proportional to the cube of the average distance of the planet from the Sun. This relationship is known as Kepler's Third Law of Planetary Motion. It describes the mathematical relationship between a planet's orbital period and its average distance from the Sun.
Because Venus has less distance to travel than the Earth and is travelling faster. With an orbital speed of 35.02 km/s and an orbital period of 224.70069 days gives an orbital distance of 679,883,169.35km The Earth has an orbital speed of 29.78 km/s (Slower than Venus) and an orbital period of 365.256 days gives an orbital distance of 939,800,765.95km
The orbital period of Saturn is 29.4571 years. Its orbital velocity is 9.69 kilometers per second and the orbital path is about 9 billion kilometers.