The strength of gravity on or near the Earth's surface
is 9.81 Newtons (2.205 pounds) per kilogram of mass.
That force causes any freely falling body to accelerate vertically
at the rate of 9.81 meters (32.2 feet) per second2 .
Its mass.
No, the weight of an object is found by multiplying its mass by the gravitational field strength: w=mg
Their masses. The strength of a planetary body's gravitational field is directly related to its mass, and its effect on an object is inversely proportional to the square of the distance between the centers of the bodies.
The larger the mass, the stronger the gravitational force.
94.3924million
Mercury's surface gravitational field strength is 0.38 times the Earth's.
Mainly, the Earth and the Moon have different masses.
There is a point where the gravitational field strength of both planet or object is equal, hence they cancel off each other, resulting in zero net gravitational field strength.
The further away from the Earth's surface you travel - the weaker the gravitational pull is.
The gravitational field strength of a planet multiplied by an objects mass gives us the weight of that object, and that the gravitational field strength, g of Earth is equal to the acceleration of free fall at its surface, 9.81ms − 2.
The gravitational field strength of Venus is about 90% of Earth's.
I assume you mean, of the gravitational field? The gravitational field is inversely proportional to the square of the distance. At a distance of 1 Earth radius, the distance from the center of the Earth is twice the distance at the Earth's surface; thus, the field strength is 1/4 what it is on the surface. If at the surface the field strength is about 9.8 meters per second square, divide that by 4 to get the field strength at a distance of one Earth radius from the surface.I assume you mean, of the gravitational field? The gravitational field is inversely proportional to the square of the distance. At a distance of 1 Earth radius, the distance from the center of the Earth is twice the distance at the Earth's surface; thus, the field strength is 1/4 what it is on the surface. If at the surface the field strength is about 9.8 meters per second square, divide that by 4 to get the field strength at a distance of one Earth radius from the surface.I assume you mean, of the gravitational field? The gravitational field is inversely proportional to the square of the distance. At a distance of 1 Earth radius, the distance from the center of the Earth is twice the distance at the Earth's surface; thus, the field strength is 1/4 what it is on the surface. If at the surface the field strength is about 9.8 meters per second square, divide that by 4 to get the field strength at a distance of one Earth radius from the surface.I assume you mean, of the gravitational field? The gravitational field is inversely proportional to the square of the distance. At a distance of 1 Earth radius, the distance from the center of the Earth is twice the distance at the Earth's surface; thus, the field strength is 1/4 what it is on the surface. If at the surface the field strength is about 9.8 meters per second square, divide that by 4 to get the field strength at a distance of one Earth radius from the surface.
Yes. It's about 38% of the strength of Earth's gravity.
Its mass.
Its mass.
The strength of the gravitational pull on your body is your weight.
Mass always remains constant but weight changes due to the change in gravitational field strength. Gravitational field strength changes because: 1. The radius of the earth is not uniform. 2. The earth is rotating about its axis. 3. The density of the earth is not uniform.