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What else can I help you with?
What is approximate distance to moon from earth's surface?
The approximate distance from the Earth's surface to the moon is about 384,400 kilometers (238,855 miles) on average.
How many km is Earth nearest to the earth?
0 because earth is no distance from earth because they are the same thing
What force of gravity exists at two times the Earth's radius?
Assuming you mean from the center of the Earth: 1/22 = 1/4, that is, 1/4 the gravity at the Earth's surface. If you mean two Earth radii from the surface, then the distance from the Earth's center would be 3 times as much, and the force would be 1/9, compared to the Earth's surface. _______________________________ The force of gravity changes with the reciprocal of the square of the distance. So if the distance is increased by a factor of 2, the force will DECREASE by a factor of two squared, or 4. So, double the distance = one-quarter the force.
How does acceleration due to gravity changes with altitude?
The acceleration of gravity ... on or near the Earth, for example ... is inversely proportional to the square of the distance from the center of the Earth. So it diminishes as you rise from the surface. When you have ascended to an altitude of one Earth radius ... about 4,000 miles ... your distance from the center is then two Earth radii, so the acceleration of gravity has shrunk to 1/4 of its value on the surface.
What would be the gravitational force on you if you were at a point in space a distance R the Earth's radius above the Earth's surface?
The gravitational force on you would be slightly less than the gravitational force on the surface of the Earth because you are further away from the Earth's center. The force would decrease with the square of the distance, so it would be calculated using the formula F = G * (m1 * m2) / r^2, where r = distance from the center of the Earth.
What is approximate distance to moon from earth's surface?
The approximate distance from the Earth's surface to the moon is about 384,400 kilometers (238,855 miles) on average.
What is the distance to the center of the earth from the surface?
The distance from the surface of the Earth to its center is approximately 6,371 kilometers.
What is the distance from the surface of the earth to the center in km?
The average distance from Earth's surface at the equator its center is about 6378 km. The distance from near the north and south poles to the center is somewhat less.
What is the Ozone layer distance from the surface of the earth?
There is no fixed distance of the ozone from surface. It is said to be an approximate of 15 to 55 km.
Is it true that over 6000 km. from the earth surface to the center of earth?
No, the distance from the Earth's surface to the center of the Earth is approximately 6,371 kilometers.
How far is the surface of the Earth to the center of the Earth?
The average distance from the surface of the Earth to the center is about 6,371 kilometers (3,959 miles).
How may miles from the earth's surface to center?
The distance from the Earth's surface to its center is approximately 3,963 miles.
What is the distance through the earth's center from surface to surface?
7,000 km
What is the distance from the surface of earth to the center is about?
Since the earth is not perfectly round, distances vary slightly. From the poles to the center its about 3950 miles. From the equator to the center its about 3960 miles The correct answer is the earth has an equitoral circumference of ~ 24,900 mi and diameter of ~ 7,926mi. With these facts we devise the surface to core distance to be ~3963mi at the equator and 3950mi from the poles.
What is the depth of the center of the earth in feet?
The center of the Earth is approximately 3,959 miles (6,371 kilometers) from the surface. Converting this distance to feet, the depth to the center of the Earth is about 20,902,880 feet.
What is the field strength at a distance one Earth radius beyond the surface?
I assume you mean, of the gravitational field? The gravitational field is inversely proportional to the square of the distance. At a distance of 1 Earth radius, the distance from the center of the Earth is twice the distance at the Earth's surface; thus, the field strength is 1/4 what it is on the surface. If at the surface the field strength is about 9.8 meters per second square, divide that by 4 to get the field strength at a distance of one Earth radius from the surface.I assume you mean, of the gravitational field? The gravitational field is inversely proportional to the square of the distance. At a distance of 1 Earth radius, the distance from the center of the Earth is twice the distance at the Earth's surface; thus, the field strength is 1/4 what it is on the surface. If at the surface the field strength is about 9.8 meters per second square, divide that by 4 to get the field strength at a distance of one Earth radius from the surface.I assume you mean, of the gravitational field? The gravitational field is inversely proportional to the square of the distance. At a distance of 1 Earth radius, the distance from the center of the Earth is twice the distance at the Earth's surface; thus, the field strength is 1/4 what it is on the surface. If at the surface the field strength is about 9.8 meters per second square, divide that by 4 to get the field strength at a distance of one Earth radius from the surface.I assume you mean, of the gravitational field? The gravitational field is inversely proportional to the square of the distance. At a distance of 1 Earth radius, the distance from the center of the Earth is twice the distance at the Earth's surface; thus, the field strength is 1/4 what it is on the surface. If at the surface the field strength is about 9.8 meters per second square, divide that by 4 to get the field strength at a distance of one Earth radius from the surface.
12. A satellite is put into an orbit at a distance from the center of the Earth equal to twice the distance from the center of the Earth to the surface. If the satellite had a weight at the surface of?
If a satellite is placed in an orbit at a distance from the center of the Earth equal to twice the Earth's radius (i.e., at a height equal to the Earth's radius), its weight would be reduced due to the inverse square law of gravitation. The gravitational force acting on the satellite at this distance is one-fourth of that on the surface, meaning it would weigh 25% of its weight at the Earth's surface. Hence, if its weight at the surface is ( W ), at this orbit it would weigh ( \frac{W}{4} ).
