The distance from the surface of the Earth to its center is approximately 6,371 kilometers.
No, the distance from the Earth's surface to the center of the Earth is approximately 6,371 kilometers.
The average distance from the surface of the Earth to the center is about 6,371 kilometers (3,959 miles).
The distance from the Earth's surface to its center is approximately 3,963 miles.
The average distance from the surface of the Earth to the center of the Earth's crust is about 33 kilometers (20.5 miles). This distance can vary depending on location, as Earth's crust is not uniformly thick.
diameter
The average distance from Earth's surface at the equator its center is about 6378 km. The distance from near the north and south poles to the center is somewhat less.
No, the distance from the Earth's surface to the center of the Earth is approximately 6,371 kilometers.
The average distance from the surface of the Earth to the center is about 6,371 kilometers (3,959 miles).
The distance from the Earth's surface to its center is approximately 3,963 miles.
7,000 km
The approximate distance from the Earth's surface to its center is about 6,371 kilometers (3,959 miles). This measurement represents the average radius of the Earth, as the planet is not a perfect sphere but slightly flattened at the poles and bulging at the equator.
Since the earth is not perfectly round, distances vary slightly. From the poles to the center its about 3950 miles. From the equator to the center its about 3960 miles The correct answer is the earth has an equitoral circumference of ~ 24,900 mi and diameter of ~ 7,926mi. With these facts we devise the surface to core distance to be ~3963mi at the equator and 3950mi from the poles.
The center of the Earth is approximately 3,959 miles (6,371 kilometers) from the surface. Converting this distance to feet, the depth to the center of the Earth is about 20,902,880 feet.
I assume you mean, of the gravitational field? The gravitational field is inversely proportional to the square of the distance. At a distance of 1 Earth radius, the distance from the center of the Earth is twice the distance at the Earth's surface; thus, the field strength is 1/4 what it is on the surface. If at the surface the field strength is about 9.8 meters per second square, divide that by 4 to get the field strength at a distance of one Earth radius from the surface.I assume you mean, of the gravitational field? The gravitational field is inversely proportional to the square of the distance. At a distance of 1 Earth radius, the distance from the center of the Earth is twice the distance at the Earth's surface; thus, the field strength is 1/4 what it is on the surface. If at the surface the field strength is about 9.8 meters per second square, divide that by 4 to get the field strength at a distance of one Earth radius from the surface.I assume you mean, of the gravitational field? The gravitational field is inversely proportional to the square of the distance. At a distance of 1 Earth radius, the distance from the center of the Earth is twice the distance at the Earth's surface; thus, the field strength is 1/4 what it is on the surface. If at the surface the field strength is about 9.8 meters per second square, divide that by 4 to get the field strength at a distance of one Earth radius from the surface.I assume you mean, of the gravitational field? The gravitational field is inversely proportional to the square of the distance. At a distance of 1 Earth radius, the distance from the center of the Earth is twice the distance at the Earth's surface; thus, the field strength is 1/4 what it is on the surface. If at the surface the field strength is about 9.8 meters per second square, divide that by 4 to get the field strength at a distance of one Earth radius from the surface.
If a satellite is placed in an orbit at a distance from the center of the Earth equal to twice the Earth's radius (i.e., at a height equal to the Earth's radius), its weight would be reduced due to the inverse square law of gravitation. The gravitational force acting on the satellite at this distance is one-fourth of that on the surface, meaning it would weigh 25% of its weight at the Earth's surface. Hence, if its weight at the surface is ( W ), at this orbit it would weigh ( \frac{W}{4} ).
The average distance from the surface of the Earth to the center of the Earth's crust is about 33 kilometers (20.5 miles). This distance can vary depending on location, as Earth's crust is not uniformly thick.
That's the Earth's radius. It's about 6378 kilometers at the equator. That's 3963 miles.