The period of an object at a distance of 1 AU from the Sun is one year. We know that, because that's Earth.
By Kepler's Third Law, something at four times the distance would have a period of the square root of the cube of 4, or the square root of 64, or, to put it simply, 8... times as long.
So, 8 years.
5
AUs
Because Venus has less distance to travel than the Earth and is travelling faster. With an orbital speed of 35.02 km/s and an orbital period of 224.70069 days gives an orbital distance of 679,883,169.35km The Earth has an orbital speed of 29.78 km/s (Slower than Venus) and an orbital period of 365.256 days gives an orbital distance of 939,800,765.95km
The Earth and Moon orbit the Sun together, a short distance apart compared with the size of the orbit. So, the Moon's orbital period is more or less identical with the Earth's. That's about 365.25 Earth days.
The greater the distance, the longer is the orbital period and the slower the velocity. "Kepler's Laws of Planetary Motion" contain mathematical details. Further explanation is given by the work of Isaac Newton and his theory of gravitation. For example, one version of Kepler's 3rd law is : The square of the orbital period (in Earth years) equals the cube of the average distance from the Sun (in Astronomical Units). <<>> The second half of the question can be answered from the above formula. For example, a planet at four times the distance of Earth from the Sun would go round the Sun in eight years. The length of that orbit would be (almost exactly) four times as far as Earth's. So, the planet would travel at half the speed of Earth. In this example, and also generally, the orbital speed is inversely proportional to the square root of the average distance from the Sun.
5
At what distance from the Sun would a planet's orbital period be 3 million years?
Yes, the equation p2 = a3, where p is a planet's orbital period in years and a is the planet's average distance from the Sun in AU. This equation allows us to calculate the mass of a distance object if we can observe another object orbiting it and measure the orbiting object's orbital period and distance.
you are chicken
Temperature and orbital period.
Temperature and orbital period.
It is the objects orbital period.
AUs
F is directly porportional to P
The distance between the sun and a planet determines its orbital period, its orbital speed, and the amount of insolation. Other factors such as composition and albedo are required to determine other variables.
This is a lot like asking: Why does the earth take 365 days to revolve around the sun ? Here's an answer, which I'm sure you'll find evasive and unsatisfying, and so it is. But when you ask "why", it really puts us out of the realm of the science, and into the philosophical realm. Kepler demonstrated, and Newton proved, that the orbital period of a light object revolving around a much more massive object under the influence of gravitation is completely determined by the dimensions of the orbit. In the case of the sun as the large central body, an average distance of 93 million miles with small eccentricity produces an orbital period of 365.25 earth days, and an average distance of 36 million miles with small eccentricity produces an orbital period of 88 earth days. 88 days is Mercury's orbital period, because 36 million miles is its distance from the sun. A grain of sand, a rock, a glob of dust, a space ship, a comet, or a planet, at the same distance from the sun, would all have an orbital period of 88 earth days.
Because it spends most of its orbital period farther from the sun than Neptune is.