A simple pendulum will not swing when it's aboard a satellite in orbit. While in
orbit, the satellite and everything in it are falling, which produces a state of
apparent zero gravity, and pendula don't swing without gravity.
A simple pendulum on the Moon would swing more slowly due to the Moon's weaker gravitational pull compared to Earth. However, the motion would still follow the same principles of a simple harmonic oscillator, with the period of oscillation proportional to the square root of the length of the pendulum.
The speed of the satellite is dependant on its distance from the surface of the planet. the greater the altitude, the greater the speed, or velocity. I would think that Velocity Equation would be a simple linear equation of the form; y=kx, where k is a constant. What that constant is for Mars, I do not know as I did not do Astronomy at Uni, only Physics subjects.
simple, we sent a satellite to orbit the moon and take pictures
Sputnik 1 was a Soviet satellite that worked by emitting radio signals that could be tracked by ground stations. It transmitted a simple radio beep to indicate its position in orbit and played a significant role in the space race by being the first artificial satellite to orbit the Earth.
The first satellite was launch in 1957 so that would mean that this year (2012) it has been around for more than half a century (55 years). +++ That first artificial satellite was launched by the USSR, who called it 'Sputnik One'. It was a simple test vehicle whose radio transmitted just a call-sign - the tune "The East Is Red" I believe. 1957 was celebrated International Geophysical Year for this and other technical achievements.
time period of simple pendulum is dirctly proportional to sqare root of length...
The time period of a simple pendulum is determined by the length of the pendulum, the acceleration due to gravity, and the angle at which the pendulum is released. The formula for the time period of a simple pendulum is T = 2π√(L/g), where T is the time period, L is the length of the pendulum, and g is the acceleration due to gravity.
The period increases as the square root of the length.
When the length of a simple pendulum is doubled, the frequency of the pendulum decreases by a factor of √2. This relationship is described by the formula T = 2π√(L/g), where T is the period of the pendulum, L is the length, and g is the acceleration due to gravity.
Compound pendulum is a physical pendulum whereas a simple pendulum is ideal pendulum. The difference is that in simple pendulum centre of mass and centre of oscillation are at the same distance.
The equation for the period (T) of a simple pendulum is T = 2π√(L/g), where L is the length of the pendulum and g is the acceleration due to gravity.
The physical parameters that might influence the period of a simple pendulum are the length of the pendulum, the acceleration due to gravity, and the mass of the pendulum bob. A longer pendulum will have a longer period, while a higher acceleration due to gravity or a heavier pendulum bob will result in a shorter period.
For a simple pendulum: Period = 6.3437 (rounded) seconds
The period increases - by a factor of sqrt(2).
multiply the length of the pendulum by 4, the period doubles. the period is proportional to the square of the pendulum length.
The time period of a simple pendulum depends only on the length of the pendulum and the acceleration due to gravity, not the mass of the pendulum bob. This is because the mass cancels out in the equation for the time period, leaving only the factors that affect the motion of the pendulum.
A compound pendulum is called an equivalent simple pendulum because its motion can be approximated as that of a simple pendulum with the same period. This simplification allows for easier analysis and calculation of its behavior.