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Who figured out that the orbital period of a planet is related to its distance from the sun?
Johannes Kepler, working with the detailed observational data compiled by Tycho Brahe, showed that the ratio of (orbital period)2 to (mean distance from the sun)3 is a constant for the earth and the five other visible planets. A generation after Kepler, Sir Isaac newton showed that his law of universal gravitation could predict the shape and periods of the planetary orbits.
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An object has been located orbiting the sun at a distance from the sun of 65 AU what is the approximate orbital period of this object?
The approximate orbital period of an object at a distance of 65 AU from the sun would be around 177 years. This corresponds to Kepler's third law of planetary motion, which relates the orbital period of a planet to its distance from the sun.
The relationship between the average distance of a planet from the sun and the planets orbital period is described by what?
Kepler's third law of planetary motion states that the square of a planet's orbital period is directly proportional to the cube of its average distance from the sun. This relationship allows us to predict the orbital period of a planet based on its distance from the sun, and vice versa.
Is the square of the orbital period of a planet proportional to the cube of the average distance of the planet from the Sun?
Yes, the square of the orbital period of a planet is proportional to the cube of the average distance of the planet from the Sun. This relationship is known as Kepler's Third Law of Planetary Motion. It describes the mathematical relationship between a planet's orbital period and its average distance from the Sun.
Why does venus take 225 days to revolve around the sun and earth takes 365 days?
Because Venus has less distance to travel than the Earth and is travelling faster. With an orbital speed of 35.02 km/s and an orbital period of 224.70069 days gives an orbital distance of 679,883,169.35km The Earth has an orbital speed of 29.78 km/s (Slower than Venus) and an orbital period of 365.256 days gives an orbital distance of 939,800,765.95km
If a planet had an average distance of 10 au what would it's orbital period be?
The orbital period of a planet can be calculated using Kepler's third law: P^2 = a^3 where P is the orbital period in years and a is the semi-major axis in astronomical units. For a planet with an average distance of 10 au, its orbital period would be approximately 31.6 years.
Which two of the planet are closely related to their distance from the sun?
Temperature and orbital period.
At what distance from the Sun would a planets orbital period be 3 million years?
A planet's orbital period is related to its distance from the Sun by Kepler's third law, which states that the square of the orbital period is proportional to the cube of the semi-major axis of the orbit. For an orbital period of 3 million years, the planet would need to be located at a distance of approximately 367 AU from the Sun.
Which two characteristics of the planet are closely related to their distance from sun?
Temperature and orbital period.
What effect has distance of a planet to the sun to its orbital period?
The distance of a planet from the sun affects its orbital period. Generally, the farther a planet is from the sun, the longer its orbital period will be. This relationship is described by Kepler's third law of planetary motion, which states that the square of a planet's orbital period is directly proportional to the cube of its average distance from the sun.
A calculation of how long it takes a planet to orbit the Sun would be most closely related to which Kepler's Law?
Kepler's 3rd law of planetary motion. It states that the square of a planets orbital period is proportional to the cube of a planets distance from a star.In mathematical notationTO2 = k*R03WhereTO = It's orbital periodRO = It's distance from the stark = A constant.
An object has been located orbiting the sun at a distance from the sun of 65 AU what is the approximate orbital period of this object?
The approximate orbital period of an object at a distance of 65 AU from the sun would be around 177 years. This corresponds to Kepler's third law of planetary motion, which relates the orbital period of a planet to its distance from the sun.
The relationship between the average distance of a planet from the sun and the planets orbital period is described by what?
Kepler's third law of planetary motion states that the square of a planet's orbital period is directly proportional to the cube of its average distance from the sun. This relationship allows us to predict the orbital period of a planet based on its distance from the sun, and vice versa.
Why is it possible for two satellites to circle the earth in orbits with identical period but different heights above the earths surface?
It's possible because the orbital period only depends on the satellite's distance from the center of the Earth, not its height above the Earth's surface. As long as the two satellites have the same distance from the center of the Earth, they will have the same orbital period even if their heights above the Earth's surface are different.
Is the square of the orbital period of a planet proportional to the cube of the average distance of the planet from the Sun?
Yes, the square of the orbital period of a planet is proportional to the cube of the average distance of the planet from the Sun. This relationship is known as Kepler's Third Law of Planetary Motion. It describes the mathematical relationship between a planet's orbital period and its average distance from the Sun.
Why does venus take 225 days to revolve around the sun and earth takes 365 days?
Because Venus has less distance to travel than the Earth and is travelling faster. With an orbital speed of 35.02 km/s and an orbital period of 224.70069 days gives an orbital distance of 679,883,169.35km The Earth has an orbital speed of 29.78 km/s (Slower than Venus) and an orbital period of 365.256 days gives an orbital distance of 939,800,765.95km
What is Saturn's rotation and orbital period?
Saturn's rotation period is about 10.7 hours, while its orbital period around the Sun is approximately 29.5 Earth years.
If a planet had an average distance of 10 au what would it's orbital period be?
The orbital period of a planet can be calculated using Kepler's third law: P^2 = a^3 where P is the orbital period in years and a is the semi-major axis in astronomical units. For a planet with an average distance of 10 au, its orbital period would be approximately 31.6 years.
