Without knowing the location of the capacitor in the amplifier (which you do not give) no specific answer can be given, only possibilities assuming various locations (e.g. input coupling, power bypass, bias networks, interstage coupling, virtual grounding of shields). Each will have one or more characteristic symptoms it could produce in the output.
The circuit becomes a pure resistance circuit where current and voltage are in phase with each others.
If a bypass capacitor is not present in an amplifier, the gain may be reduced due to increased emitter resistance, which can negatively affect the amplifier's frequency response. This could lead to poor performance, particularly in AC signal amplification, as the capacitor typically helps to stabilize the biasing and improve AC gain by providing a low impedance path for AC signals. Additionally, the absence of the bypass capacitor may result in unwanted feedback and reduced overall efficiency of the amplifier circuit.
When a capacitor is connected to a circuit, the current flow through the capacitor initially increases and then decreases as the capacitor charges up.
What happens to the current in a circuit as a capacitor charges depends on the circuit. As a capacitor charges, the voltage drop across it increases. In a typical circuit with a constant voltage source and a resistor charging the capacitor, then the current in the circuit will decrease logarithmically over time as the capacitor charges, with the end result that the current is zero, and the voltage across the capacitor is the same as the voltage source.
An open circuit, by definition, has no continuity, therefore there is no current flow. A failed capacitor in an open circuit would have absolutely no effect.
A capacitor discharges when it releases the stored electrical energy it has accumulated. This typically happens when the capacitor is connected to a circuit or load that allows the energy to flow out of the capacitor.
The capacitors allow the signal to pass through, while 'blocking' the DC voltage level that the signal is 'riding' on. Are you asking to remove the capacitor and connect it straight through? If you had a multistage amplifier, then the DC riding voltage would try to get amplified as well, and the next stage amplifier would probably 'max out' and you'd wind up with just solid DC output, or components further along in the circuit could be damaged. If you're asking if the capacitor was taken out (like if it blew) then no signal would get through.
There's no effect since the capacitor was already faulty i.e it was like not in the circuit. Install a healthy capacitor because it will improve the power factor of the fluorescent lamp circuit thus reducing energy wasted.
In a DC circuit, if the capacitance value becomes infinite, the capacitor would essentially act as a short circuit after it is fully charged. Initially, it would allow current to flow while charging, but once charged, it would maintain a constant voltage across its terminals and prevent any further current flow. This means that the capacitor would no longer store energy or affect the circuit's operation beyond its initial charging phase.
When the capacitor is removed from a circuit containing a lamp, the behavior of the lamp depends on the circuit configuration. In a basic circuit where the capacitor is used for filtering or smoothing, the lamp may flicker or turn off due to the loss of charge stabilization, leading to inconsistent voltage. If the capacitor is part of a timing or oscillation circuit, the lamp may stop functioning altogether. Overall, the removal of the capacitor typically disrupts the normal operation of the lamp.
A voltage error circuit is called an error amplifier and happens when there are discrepancies between the voltage output and the reference voltage. A current error circuit happens when there is a disruption of flow in an ammeter.
It must (i) increase, or (ii) decrease, or (iii) stay the same. If (iii), there's no point in having it at all, so consider what happens to stage gain at the lowest frequencies, as the capacitor has less and less effect on the circuit.