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A basketball player can leap upward .5m what is the initial velocity at the start of the leap?
Alphacappapi
You can answer this question using the following kinematics equation:
v2 = vi2 +2a(x-xi)
where v is the final velocity, vi is the initial velocity, a is the acceleration, x is the final position and xi is the initial position.
The displacement (x-xi) is given as 0.5m, and since the person is jumping upwards, the acceleration (a) is the acceleration due to gravity, or 9.8 m/s2. The acceleration is negative because it is pointing towards the earth, opposite the direction of her jump. The final velocity (v) is 0, since it is being considered at the peak of the jump. Using this information, solve for vi.
v2 = vi2 +2a(x-xi)
0 = vi2 + 2(-9.8)(0.5)
0 = vi2 + (-9.8)
9.8 = vi2
sqrt(9.8) = sqrt(vi2)
3 m/s = vi
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