Answering "Experiment on the effect of the PH of enzymatic reaction using hydrogen peroxide and extract of spinach leaf?"
A substrate is a substance in which an enzyme reacts. The substrate for catalase would be hydrogen peroxide otherwise known as H2O2.
Equipment: - Hydrogen Peroxide - Catalase - Equally sized paper slips (a small rectangle, 2 cm X 1 cm) - Tweezers - Beaker - Stopwatch -pH testing strips -Acids (lemon juice, vinegar, etc.) -Bases (milk, baking soda, ammonia etc.) For the control, take one of the paper slips, using the tweezers, and dip it into the catalase, then place the catalase covered slip at the bottom of a beaker filled about halfway with hydrogen peroxide. You cannot simply drop the slip into the beaker, you must stick the tweezers into the beaker so that they reach the bottom, and then release. When the catalase contacts the hydrogen peroxide the hydrogen peroxide will release oxygen as a reaction, these oxygen bubbles in the liquid will push the paper to the top. Start the stop watch precisely when the strip enters the hydrogen peroxide, to measure the rate of reaction, and stop it again when the slip reaches the top. And finally for the affect of pH on the enzyme, simply change the pH of the hydrogen peroxide adding an acid, or a base. Then, just rerun the experiment and it will be evident that the pH affects the rate of reaction. The pH of hydrogen peroxide is roughly 2, or in that region, so adding a base will speed up the reaction, because the pH optimum of catalase is around 7.
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An example of spontaneous decomposition is that of hydrogen peroxide, which will slowly decompose into water and oxygen: : 2H2O2 → 2H2O + O2 thus it would be a degradative reaction
Catalase is an enzyme that is substrate-specific, meaning that it has a particular reaction that it will catalyze (to speed up a reaction). Hydrogen peroxide (H2O2) is the specific substrate reactant with which catalase will react (in a degradation reaction). This is the degradation (breaking down of) reaction. 2H2O2 yields 2H2O+O2 O2 is oxygen which is indicated by the rising of bubbles upon reaction between the hydrogen peroxide and the catalase. Sucrose is not the specific substrate assigned to the catalase enzyme, therefore they will not react together in a degradation reaction, hence the lack of oxygen release (lack of bubbles). I hope this was helpful to you. God bless and Jesus loves you.
Catalase is an enzyme that is present in potatoes that catalyzes the decomposition of the hydrogen peroxide into H20 (water) and O2 (oxygen). This oxygen that is being formed in the enzymatic reaction is the cause for the bubbles that you see forming.
reaction betwen sodiumbisulphite and hydrogen peroxide
having just done this experiment for my chemistry lab, i found that adding it to hydrogen peroxide produces a similar reaction as adding it to water. it dissolves almost as fast.
No reaction will occur.
Hydrogen Peroxide decomposes in oxygen gas and water.
Hydrogen peroxide is an oxidising agent, and oxidation is an exothermic reaction. The liver is being oxidised.
Catalase is the endozyme that then degrades hydrogen peroxide into water and oxygen
This is a chemical reaction. A decomposition reaction.
The reaction of common household hydrogen peroxide is rather boring. But pure H2O2 (hydrogen peroxide) mixed with sugar which is C12H22O11 results in the production of H2O and CO2.
The hydrogen peroxide foams.
yes
yes