First, draw a box, then divide it in four.
Let's say we're testing for the genotypes of the offspring of parents with TT and Tt genotypes. Above the first box, write one allele of a parent, or in this case, T. Above the box to the right of it, write another T for the parents' other allele. Do the same down the left side of the four boxes with the other parent's genes.
Now, this is a bit like finding coordinates. In the first box, write the allele of the gene above it, and to its left. That is one possible genotype of the offspring. Repeat this for all squares.
In our case with the parents being TT and Tt, the four offspring in the Punnett squares will have only two possible genotypes; TT or Tt, like their parents.
This will show you how many chances the offspring have of being heterozygous, homozygous dominant, or recessive.
of two different phenotypes
You can use a Punnet Square to figure it out. For example, if gray elephants dominate over brown elephants, and you cross 1 homozygous gray elephant (GG) and one homozygous brown elephant (gg), the Punnet square predicts that the offspring will all be heterozygous Gg. They will all be gray, however, because gray dominates over brown.
1 will be hemozygous tall TT(25%), 2 will be heterygous tall Tt(50%), and 1 will be dwarf tt.........tatal, 75% will be tall
If tall (T) is dominant and small (t) is recessive, and both are homozygous, they would all be tall. (100% tall, heterozygous.) If the tall is heterozygous, it would be 50% tall heterozygous and 50% short heterozygous.
100 Black Bodies.
25%
36
3
of two different phenotypes
You can use a Punnet Square to figure it out. For example, if gray elephants dominate over brown elephants, and you cross 1 homozygous gray elephant (GG) and one homozygous brown elephant (gg), the Punnet square predicts that the offspring will all be heterozygous Gg. They will all be gray, however, because gray dominates over brown.
120 on average or 50%. 25% would be homozygous dominant and 25% would be homozygous recessive. The remaining 50% would be heterozygous.
Two types: A heterozygous parent (Aa) and a homoygous recessive parent (aa) can produce phenotypically dominate and phenotpically recessive offspring (with 50% genotypes Aa and the other 50% aa). If the genes are co-dominate then the offspring can have blended traits and recessive traits phenotypically.
The offspring has a 50% chance of the dominate trait (while being heteroygous) and a 50% chance of having the recessive trait ( homozygous recessive).
1 will be hemozygous tall TT(25%), 2 will be heterygous tall Tt(50%), and 1 will be dwarf tt.........tatal, 75% will be tall
A trait that exhibits incomplete dominance, is one in which the heterozygous offspring will have a phenotype that is a blend between the two parent organisms. An example of this is when a homozygous red sweet pea flower crossed with a homozygous white sweet pea flower, their offspring will be heterozygous and have the pink phenotype, rather than either red or white. So, the homozygous red flower will be red, the homozygous white flower will be white, and the heterozygous flower will be pink. So there are three possible phenotypes in incomplete dominance. There are also no dominant or recessives genotypes.
Generally, in sexual reproduction, two parents make offspring.
It depends on which trait is dominant and whether the silver-blue mink is homozygous or heterozygous.