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The poly adenine tail is used to provide a fuse. This is because RNase enzymes cleave off a section of the nucleotides at the end of the mRNA strand. The destruction of the mRNA is to prevent it persisting within the cell after being used, the length of the tail shows how many times it will be used before being degraded.
The amino acid sequence is: UUU-UCU-UCC-CCU-CGG-CGA-AGG-AUU.
aau uut tta aat which is it
The matching anticodon for UUU is AAA. A ribosome pairs the UUU codon on the mRNA with the AAA anticodon on the tRNA during protein synthesis.
AA X aa= 4 Aa======the only possible cross between a true breeding homozygous dominant and a true breeding homozygous recessive.
TAC AAA TTT GCA ACC ACT (DNA) AUG UUU AAA CGU UGG UGA (mRNA)
The poly adenine tail is used to provide a fuse. This is because RNase enzymes cleave off a section of the nucleotides at the end of the mRNA strand. The destruction of the mRNA is to prevent it persisting within the cell after being used, the length of the tail shows how many times it will be used before being degraded.
The amino acid sequence is: UUU-UCU-UCC-CCU-CGG-CGA-AGG-AUU.
aau uut tta aat which is it
The matching anticodon for UUU is AAA. A ribosome pairs the UUU codon on the mRNA with the AAA anticodon on the tRNA during protein synthesis.
AUA - Ile, AGC - Ser, GCU - Ala, and AAA is Lysine.
The DNA sequence 5' AUG AAA UAA 3' translates to the mRNA sequence 5' AUG AAA UAA 3'. The start codon AUG codes for methionine, and the UAA codon serves as a stop codon, indicating the end of the protein-coding region.
AGT codes for the amino acid serine and CTT codes for the amino acid leucine.
Anticodons are sequences of three base pairs on a transfer RNA that correspond to (and subsequently pair up with) codons on messenger RNAs. These complementary pairs come together by forming hydrogen bonds. For example, a tRNA with the anticodon UUU may correspond to the codon AAA on the mRNA.
Because restriction enzymes recognised site normally are more than one.For example, if an enzyme recognise three Base pair such us AAA and the copy segment of DNA has 5 AAA segment than the enzyme will cut the DNA into 5 picies.
AA X aa= 4 Aa======the only possible cross between a true breeding homozygous dominant and a true breeding homozygous recessive.
AAa