you cant just put Dd on a punnet square you have to have two of them like dd,DD or Dd,dd you can also have the same one twice
In this case, the mother does not have dimples (Dd) but the father does not have dimples (dd). The Punnett square would show that half of the offspring would have dimples (Dd) and the other half would not have dimples (dd).
50%. There are four possible outcomes of the cross:dominant trait from "dad", dominant trait from "mom"recessive trait from "dad", dominant trait from "mom"dominant trait from "dad", recessive trait from "mom"recessive trait from "dad", recessive trait from "mom"Therefore, to get hybrid offspring (one dominant, one recessive), you have a 2 out of 4 chance.
Phenotype is the observed trait. The dominant trait in this case is observed- D
If 75 offspring have a Dominant gene, then the parents must have at least one Dominant gene each. This would make them either Dominant Homozygous (DD) or Heterozygous (Dd) for the Dominant trait.
If two homozygous plants with contrasting traits are crossed, the expected genotypes for the offspring will be heterozygous. The dominant trait would be expressed, but they'd be carriers for the recessive trait.
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In this case, the mother does not have dimples (Dd) but the father does not have dimples (dd). The Punnett square would show that half of the offspring would have dimples (Dd) and the other half would not have dimples (dd).
50%. There are four possible outcomes of the cross:dominant trait from "dad", dominant trait from "mom"recessive trait from "dad", dominant trait from "mom"dominant trait from "dad", recessive trait from "mom"recessive trait from "dad", recessive trait from "mom"Therefore, to get hybrid offspring (one dominant, one recessive), you have a 2 out of 4 chance.
Phenotype is the observed trait. The dominant trait in this case is observed- D
75%. Explanation: if both parents are carriers than their Gametes would be Dd x Dd, resulting in DD (1/4), Dd (2/4), and dd(1/4), meaning that there is a 25% chance that they will have a child that has the disorder. DD = A normal child that lacks the recessive gene, therefore not a carrier Dd = A normal child that carries the recessive gene dd = A child with the disorder + carries the gene, hence the child's future offspring will carry it as well. Source: Self/Basic Punnet Square
Homozygous Dominant for a trait means that an organism has two dominant alleles for that trait. Here's an example: Trait: Widow's Peak Widow's Peak allele: Dominant (D) No widow's peak allele: Reccessive(d) Homozygous Dominant (DD) Homozygous Reccessive (dd) Heterozygous (Dd)
A Punnett square for two dwarfs would show the possible combinations of alleles for the dwarf trait. Since dwarfs are homozygous for the dwarf allele (dd), the Punnett square would always yield offspring with the genotype dd when crossed with another dwarf. Therefore, the Punnett square for two dwarfs would show all offspring as dwarfs with the genotype dd.
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If the gene for a trait has two alleles, one dominant (D) and one recessive (d) there are three possible combinations in the genotype: DD (homozygous dominant) Dd (heterozygous) dd (homozygous recessive)
If 75 offspring have a Dominant gene, then the parents must have at least one Dominant gene each. This would make them either Dominant Homozygous (DD) or Heterozygous (Dd) for the Dominant trait.
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If two homozygous plants with contrasting traits are crossed, the expected genotypes for the offspring will be heterozygous. The dominant trait would be expressed, but they'd be carriers for the recessive trait.