They must both be OB (heterozygous). * OB produces B type * BB produces B type * OO produces O type We project that 1/4 of offspring will be BB, 1/2 will be OB, and 1/4 will be OO. Since BB and OB have the same phenotype (blood type B), statistically 3/4 will be type B and 1/4 will be type O.
So, if one parent is Aa (heterozygous) and the other parent is aa (homozygous recessive) the punnett square would look like this: ___|_A__|__a_ _a_|_Aa_|_aa_ _a_|_Aa_|_aa_ The genotypes of the offspring 50% heterozygous and 50% homozygous recessive
Alright, I suppose I will do your homework for you.. Here is your punnet square: F F F FF FF f Ff ff Therefore, 3/4, or 75%, offspring will have the phenotype of having freckles, and 1/4, or 25% will have the phenotype of no freckles. And 2/4, or 50%, of the offspring will have the genotype for homozygous for freckles, 1/4, or 25%, of the offspring will carry a heterozygous trait for freckles, and 1/4, or 25%, of the offspring will have the phenotype for homozygous no freckles.
Genotype: AA - The phenotype is homozygous dominant, exhibiting the dominant trait. Genotype: Aa - The phenotype is heterozygous, exhibiting the dominant trait. Genotype: aa - The phenotype is homozygous recessive, exhibiting the recessive trait.
There are 3 probabilities: dominant homozygous, recessive homozygous, or heterozygous.
The possible genotypes of the offspring are Bb (heterozygous blue) and bb (white). The possible phenotypes are blue and white flowers. Each offspring will inherit one allele from each parent, resulting in a 50% chance of being blue (Bb) and 50% chance of being white (bb).
In a cross between a homozygous recessive parent (AA) and a heterozygous parent (Aa), the possible genotypes of the offspring are 50% homozygous recessive (AA) and 50% heterozygous (Aa). Therefore, the probability that an offspring will be homozygous recessive is 50%.
To determine if a plant is homozygous or heterozygous, you would need to test cross it with a homozygous recessive plant. If the offspring show the recessive trait, the original plant is heterozygous; if all offspring show the dominant trait, the original plant is homozygous.
So, if one parent is Aa (heterozygous) and the other parent is aa (homozygous recessive) the punnett square would look like this: ___|_A__|__a_ _a_|_Aa_|_aa_ _a_|_Aa_|_aa_ The genotypes of the offspring 50% heterozygous and 50% homozygous recessive
Alright, I suppose I will do your homework for you.. Here is your punnet square: F F F FF FF f Ff ff Therefore, 3/4, or 75%, offspring will have the phenotype of having freckles, and 1/4, or 25% will have the phenotype of no freckles. And 2/4, or 50%, of the offspring will have the genotype for homozygous for freckles, 1/4, or 25%, of the offspring will carry a heterozygous trait for freckles, and 1/4, or 25%, of the offspring will have the phenotype for homozygous no freckles.
To determine the genotype of an individual who is heterozygous for a trait, you would need to perform a genetic cross with a homozygous recessive individual. By observing the phenotypes of the offspring, you can deduce the genotype of the heterozygous individual. This can help determine if the heterozygous individual is carrying one dominant and one recessive allele.
To determine if a particular plant is homozygous or heterozygous, you would need to perform a test cross with a homozygous recessive individual. If the offspring display the recessive trait, the original plant would likely be heterozygous. If all offspring exhibit the dominant trait, the original plant would likely be homozygous dominant.
A cross between two individuals that are homozygous for different alleles will only produce heterozygous offspring. This is because each parent can only donate one type of allele, resulting in all offspring being heterozygous for that particular gene.
To determine the hair color of the guinea pigs' offspring, we need to know the genotypes of the parents. If one parent is homozygous dominant (BB) and the other is homozygous recessive (bb), all offspring will be heterozygous (Bb) and will have black hair. If both parents are heterozygous (Bb), approximately 25% of the offspring are expected to be homozygous dominant (BB), 50% heterozygous (Bb), and 25% homozygous recessive (bb), resulting in a 75% chance of black hair and a 25% chance of white hair.
If the parent generation consisted of a homozygous dominant parent and a homozygous recessive parent, then the F1 generation would be 100% heterozygous.
The scientist should perform a test cross between the organism and a homozygous recessive organism. If all offspring show the dominant trait, the original organism is homozygous dominant. If some offspring show the recessive trait, the original organism is heterozygous.
The genotype of the offspring with yellow pods is likely homozygous dominant (YY) or heterozygous (Yy), assuming yellow pods are dominant over green. The possible genotypes of the offspring with green pods would be homozygous recessive (yy), as green is the recessive trait. If both yellow-podded parents are heterozygous (Yy), some offspring could also be yellow (YY or Yy) while others could be green (yy).
Genotype: AA - The phenotype is homozygous dominant, exhibiting the dominant trait. Genotype: Aa - The phenotype is heterozygous, exhibiting the dominant trait. Genotype: aa - The phenotype is homozygous recessive, exhibiting the recessive trait.