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If you wanted to remove essentially all of the glucose from a glucose water solution how would you do it using a cellulose bag a large beaker and water?
Wiki User
∙ 12y ago
immense the glucose solution in cellulose bag in to the beaker for about 30minutes, more water will diffuse through the selective permeable membrane of the bag leaving the sugar. simple take out the bag,stand in a dry baker and test for glucose using a Benedict solution which indicate the finale result of the experiment.
Wiki User
∙ 12y ago
Wiki User
∙ 13y agoThat is very difficult because glucose is highly soluble in water, however you could try to crystallize it by boiling off the water until the glucose is saturated, then cooling it to slightly below 0 C (don't worry, the water won't freeze). Then filter the solid that forms.
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A balloon permeable to water but not to glucose contains a 10 percent glucose solution A beaker contains a 5 percent glucose solution the solution in the balloon is what?
the solution in the balloon is hypertonic relative to the solution in the breaker. is this true
If a beaker contains glucose and is permeable to glucose what will happen to the glucose?
If a beaker containing glucose is permeable to glucose, then the glucose will go through the beaker.
How does Lugol's solution work as an indicator?
An indicator is a substance that changes colour in the presence of another substance. Let say inside the beaker are substances of both glucose and starch. The glucose and starch are of same colour. By injecting the lugol's solution into the beaker, the lugol's solution changes colour in the area of where starch is, while no colour changes in the presence of glucose. Thus, by using the Lugol's solution which only acts as indicator for starch and not glucose, we could tell part which area floats around with glucose and starch substances. Lugol's solution works as an indicator because it will stain starches due to iodine's interaction with the coil structure of the polysaccharide.
What will happen if you pour starch indicator solution into the cell and filled the beaker with starch and glucose solution?
The starch indicator solution will diffuse out of the bag (cell) into the beaker, changing the color of the starch solution to a blue, purple, or black color (assuming that it's iodine). The color of the indicator solution inside the bag will not change, because only the glucose can diffuse into the bag, but the starch cannot diffuse into the bag.
A bag with a 2 percent solution is placed in a beaker that has a 10 percent solution is the solution in the bag hypotonic hypertonic or isotonic?
hypertonic
A balloon permeable to water but not to glucose contains a 10 percent glucose solution A beaker contains a 5 percent glucose solution the solution in the balloon is what?
the solution in the balloon is hypertonic relative to the solution in the breaker. is this true
If a beaker contains glucose and is permeable to glucose what will happen to the glucose?
If a beaker containing glucose is permeable to glucose, then the glucose will go through the beaker.
How does Lugol's solution work as an indicator?
An indicator is a substance that changes colour in the presence of another substance. Let say inside the beaker are substances of both glucose and starch. The glucose and starch are of same colour. By injecting the lugol's solution into the beaker, the lugol's solution changes colour in the area of where starch is, while no colour changes in the presence of glucose. Thus, by using the Lugol's solution which only acts as indicator for starch and not glucose, we could tell part which area floats around with glucose and starch substances. Lugol's solution works as an indicator because it will stain starches due to iodine's interaction with the coil structure of the polysaccharide.
What will happen if you pour starch indicator solution into the cell and filled the beaker with starch and glucose solution?
The starch indicator solution will diffuse out of the bag (cell) into the beaker, changing the color of the starch solution to a blue, purple, or black color (assuming that it's iodine). The color of the indicator solution inside the bag will not change, because only the glucose can diffuse into the bag, but the starch cannot diffuse into the bag.
A model cell half full of an aqueous solution of glucose with a membrane that is permeable to glucose is placed into a beaker of distilled water Explain what is likely to happen?
do you go to UTAS? that is not an answer how is this going to help people ????
What would happen if you poured starch indicator solution into the cell and filled the beaker with starch and glucose solution?
Well what i think is that The water outside of the "cell" will change colors and not the "cell" :D
Why did copper in the solution plate the spoon and no the beaker?
The copper and the metal of the spoon have a chemical attraction to one another and form bonds. Glass is essentially inert, and does not form bonds with metals in solution.
How can you tell if glucose starch water and iodine passes through the cell membrane?
place starch solution inside the partially permeable membrane and than partially submerge it a beaker filled with distilled water. after some time, take the tubing out and test the water inside the beaker for starch by adding iodine solution. if the tubing is permeable to starch, the starch would have diffused into the water in the beaker and test positive for starch and turn dark blue. if not, then the water in the beaker would test negative for starch and remain a yellowish brown solution.
What is chemical system?
A chemical system consists of the system and the surroundings. If you're dealing with a solution in a beaker, the solution would be the system and the beaker and air would be the surroundings.
What is it called when the solution settle to the bottom of a beaker?
hotter
What is the density of 40ml of saline solution in 50 ml beaker?
The density of 40ml of saline solution in a 50 ml beaker is 1.0046g/mL. The density will vary based upon the concentration of the salt added to the solution.
Why must the stem of the funnel touches the inside surface of the collecting beaker during the filtration?
it's done to minimize the mixing of air into the filtered solution. By touching the stem to the collecting beaker, the solution flows into the beaker smoothly rather than splashing into it.
