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A white-eyed male fruit fly would have the genotype "X^wY," where "X^w" represents the recessive white eye allele on the X chromosome and "Y" represents the Y chromosome.
The "X" stands for the X chromosome. In fruit flies, the letter "X" is used to represent the sex chromosome that carries the gene controlling eye color. The genotype XRXR indicates that the individual has two copies of the X chromosome, with both carrying the dominant allele for red eyes.
If black body color is recessive and gray is dominant, we can assume that the black body color is represented by the genotype "bb". Given that gray is dominant, individuals with gray bodies could be either "GG" or "Gg". Thus, for black body color to appear in offspring from two gray-bodied flies, both parents would need to be carriers of the black body allele (each "Gg" or "gg"). Therefore, if both parents are carriers, the expected ratio of black-bodied offspring would be 25% (1/4). In a sample size of 200 offspring, we would expect around 50 flies to have black bodies.
Yes. the phenotype is the visible manifestation of a genotype. In the example of fruit flies, if red eyes are dominant and white eyes recessive, than the genotypes "AA" and "Aa" will give a dominant phenotype of red eyes. Conversely, a recessive "aa" will give a phenotype of white eyes.
If one fruit fly is heterozygous for long wings and the other is homozygous for short wings, the expected percentage of their offspring having long wings would be 50%. This is because when the long-winged parent passes on the dominant long-wing allele and the short-winged parent passes on the recessive short-wing allele, the offspring would have one of each allele, resulting in the offspring having long wings.
A white-eyed male fruit fly would have the genotype "X^wY," where "X^w" represents the recessive white eye allele on the X chromosome and "Y" represents the Y chromosome.
The "X" stands for the X chromosome. In fruit flies, the letter "X" is used to represent the sex chromosome that carries the gene controlling eye color. The genotype XRXR indicates that the individual has two copies of the X chromosome, with both carrying the dominant allele for red eyes.
In a typical P cross involving fruit flies (Drosophila melanogaster), the male parent genotype can be represented using allele symbols that reflect its traits. For example, if the male is homozygous for a dominant allele (e.g., "AA") or heterozygous (e.g., "Aa"), these symbols indicate the alleles present for a specific trait. If the traits involved are eye color, for instance, "w+" could represent a wild-type allele for red eyes, while "w" represents the recessive allele for white eyes. Therefore, if the male parent has red eyes and is homozygous, his genotype would be "w+w+"; if heterozygous, it would be "w+w".
The genotype for a white-eyed male fruit fly is X^wY, where X^w represents the white eye color allele on the X chromosome and Y represents the Y chromosome. In fruit flies, eye color is located on the X chromosome, so males only have one copy of the eye color gene.
The statement, "In fruit flies, gray body color is dominant over black body color" is true. The allele for gray body color is dominant.
Dumpy wings in fruit flies are a recessive trait. This means that an individual must inherit two copies of the dumpy wing allele (one from each parent) in order to exhibit the dumpy wing phenotype. Dominant traits, on the other hand, only require one copy of the allele to be expressed. In the case of dumpy wings, the presence of the wild-type allele (normal wings) masks the expression of the dumpy wing allele, making it recessive.
If black body color is recessive and gray is dominant, we can assume that the black body color is represented by the genotype "bb". Given that gray is dominant, individuals with gray bodies could be either "GG" or "Gg". Thus, for black body color to appear in offspring from two gray-bodied flies, both parents would need to be carriers of the black body allele (each "Gg" or "gg"). Therefore, if both parents are carriers, the expected ratio of black-bodied offspring would be 25% (1/4). In a sample size of 200 offspring, we would expect around 50 flies to have black bodies.
Yes. the phenotype is the visible manifestation of a genotype. In the example of fruit flies, if red eyes are dominant and white eyes recessive, than the genotypes "AA" and "Aa" will give a dominant phenotype of red eyes. Conversely, a recessive "aa" will give a phenotype of white eyes.
Assuming that we are talking about fruit flies, then you should be able to determine this. Gray bodied flies would be the dominant and ebony bodied flies would be recessive. So, the results can only be a homozygous dominant fly (GG) or heterozygous fly (Gg). If you cross that fly with a ebony bodied fly (gg) and there is a result of some ebony bodied flies, then you know the original fly was heterozygous. If you result in all gray flies, then it was dominant.Source(s):Biology 101
If one fruit fly is heterozygous for long wings and the other is homozygous for short wings, the expected percentage of their offspring having long wings would be 50%. This is because when the long-winged parent passes on the dominant long-wing allele and the short-winged parent passes on the recessive short-wing allele, the offspring would have one of each allele, resulting in the offspring having long wings.
Yes.
In this cross, all offspring will have straight wings since the homozygous fly can only pass on the dominant allele for straight wings (SS) while the heterozygous fly can pass on either straight (S) or curled wings (s). Therefore, all offspring will inherit one straight wing allele, resulting in them having straight wings.