It may not be a "mutant" allele but a recessive allele that offers other (perhaps yet-unknown) benefits. Or, it has never caused a significant enough problem to have evolved out of the genome.
An albino has all recessive genes for pigmentation. Hence there is no expression for pigment. In other words the genotype of an albino is homozygous recessive.
Both parents would each have one dominant gene for normal pigmintation and each would have one recessive albino gene. Say P is the dominant gene and q is the albino gene. Then the parents genotype would both be Pq. Below is a Punnet Square. The child's genotype is qq P q ------------------------------------- P / PP / Pq (carrier) / / / / ///////////////////////////////////////// q / Pq (carrier) / qq (albino) / / / / ////////////////////////////////////////
melanin
Albinism is a sex-linked trait. Accordingly, the description of "heterozygous male" doesn't make sense. The sex chromosomes for males are XY, and usually genetic disorders are passed down by the X chromosome (which is the case for albinism). So in the problem, we aren't sure whether the male is XaY or XAY. It would be more helpful to know if the male was albino or not; we would then immediately know his genotype. We can, however, figure out the genotype of the female. Because albinism is recessive, we can deduce that her genotyple is XaXa. But without knowing the male's genotype or phenotype, the offspring percentages cannot be calculated.
Albinism is a recessive trait, meaning that an albino person has the genotype AA, while a person who isn't albino has the trait Aa or AA. Two albino people (AA x AA) will have all albino children. Aa x AA will have a 50% probability of albino children, and 50% normal children who are carriers (Aa). AA x AA will have all normal children who are carriers (Aa). Aa x Aa will have 25% AA (normal/non carriers), 25% AA (albino), and 50% Aa (normal/carriers) offspring. AA x AA will have all normal children who are not carriers (AA).*A person who has the genotype Aa is a carrier because they carry the allele (a) for albinism but they are not albino. The allele (A) is dominant so it covers the (a) allele.
An albino has all recessive genes for pigmentation. Hence there is no expression for pigment. In other words the genotype of an albino is homozygous recessive.
Albinism is genetically determined.
Both parents would each have one dominant gene for normal pigmintation and each would have one recessive albino gene. Say P is the dominant gene and q is the albino gene. Then the parents genotype would both be Pq. Below is a Punnet Square. The child's genotype is qq P q ------------------------------------- P / PP / Pq (carrier) / / / / ///////////////////////////////////////// q / Pq (carrier) / qq (albino) / / / / ////////////////////////////////////////
biological inheritance of genetically recessive alleles (genes)
Albino snakes are able to survive in the wild by staying out of sight and doing their best to camouflage into their environments. However, sometimes they are unable to survive in the wild.
they can survive like you and I without too many problems
Each parent is heterozygous for the gene.
melanin
50 are produced
Mine didn't.
Yes, just like many other animals, there can be kangaroos which grow white fur. On occasion, there are even albino kangaroos. This occurs genetically when an animal has no pigment in it's cells, causing the skin and fur to be completely white and the irises in the eye to be red. Albino animals don't survive very long in the wild because their lack or coloring and camoflage makes then very easy targets for predators.
Albinism is a sex-linked trait. Accordingly, the description of "heterozygous male" doesn't make sense. The sex chromosomes for males are XY, and usually genetic disorders are passed down by the X chromosome (which is the case for albinism). So in the problem, we aren't sure whether the male is XaY or XAY. It would be more helpful to know if the male was albino or not; we would then immediately know his genotype. We can, however, figure out the genotype of the female. Because albinism is recessive, we can deduce that her genotyple is XaXa. But without knowing the male's genotype or phenotype, the offspring percentages cannot be calculated.