The voltage would be the difference in the voltages of the two cell since one cell will be giving a positive voltage and the other will be giving a negative voltage.. For instance, of both cells were your standard 1.5v cell, the total of two in series opposition would be 0 because 1.5v + -1.5v = 0v. If one of the cells was slightly used and had a voltage of 1.47v then you would end up with a voltage of -0.03v. That is, 1.47 + -1.5v. Flip the cells around and you will get +0.03v since 1.5v + -1.47v = 0.03v. Hope that makes sense.
How does the voltage measured across a dry cell ompare with the voltage drop measured across three bulbs in series?
P
Batteries
excitablity
carbon
The voltage increases in this case.
Yes.
There is addition of voltage. Dry cells have 1.5 volts irrespective of there size. if the cells are added as same polarity in series it will add if are parallel then voltage remains same
The voltage will be double that of one dry cell. The current will be that of one dry cell.
It depends on what the 6 cells are, but the battery voltage is just 6 times the cell voltage. In a car battery (lead-acid cells) - 12V In a dry-battery (zinc-carbon cells) - 9V
"series" ... high voltage
Opposition to voltage changes in a wire is called back EMF or counter EMF.See related links below.
7.5 Volts
"series" ... high voltage
1.5v+1.5v+`n batteries. You didn't say how many cells, but if they're wired in series, the voltage is additive. 7.5 volts
Voltage between points A and B creates the tendency for current to move. While you have the voltage you need, your little dry cells can't generate enough current through the motor to overcome the resistance of the engine. They just don't have enough juice stored in them.
Add distilled water to the battery cells. Get the water just so each cell in underwater. And then find out why it is dry. Could be the voltage regulator is defective and the battery is being overcharged.