To find the molarity of the solution, divide the number of moles of solute (0.49 mol) by the volume of the solution in liters (6.32 L). This gives a molarity of approximately 0.077 M.
The concentration of the solution is measured in moles per liter (mol/L).
The molarity of the solution can be calculated by dividing the number of moles of solute by the volume of the solution in liters. Therefore, the molarity of the solution is 0.400 mol / 9.79 L = 0.041 mol/L.
The total moles of solute and solvent in the solution is 9.0 mol. The mole fraction of methanol would be the moles of methanol divided by the total moles. Therefore, the mole fraction of methanol in the solution is 6.0 mol / 9.0 mol = 0.67.
The molarity of a solution with 3 mol of glucose in 6 kg of water cannot be determined without knowing the volume of the solution. Molarity is defined as the amount of solute (in mol) divided by the volume of the solution in liters. Without the volume, the molarity of the solution cannot be calculated.
4 mol/0.800 kg
The concentration of the solution is measured in moles per liter (mol/L).
The molarity of the solution can be calculated by dividing the number of moles of solute (0.202 mol KCl) by the volume of the solution in liters (7.98 L). So, molarity = 0.202 mol / 7.98 L ≈ 0.025 mol/L.
The mole fraction of NaCl in the solution is calculated by dividing the moles of NaCl by the total moles of NaCl and water. In this case, the mole fraction of 18 mol NaCl in a solution of 100 mol water is 0.15 (18 mol NaCl / (18 mol NaCl + 100 mol water)).
The molarity of the solution can be calculated by dividing the number of moles of solute by the volume of the solution in liters. Therefore, the molarity of the solution is 0.400 mol / 9.79 L = 0.041 mol/L.
A 25 millimole (m mol) solution means there are 25 millimoles of solute in every liter of solution. It is a unit used to express the concentration of a solute in a solution.
The total moles of solute and solvent in the solution is 9.0 mol. The mole fraction of methanol would be the moles of methanol divided by the total moles. Therefore, the mole fraction of methanol in the solution is 6.0 mol / 9.0 mol = 0.67.
The molarity of a solution with 3 mol of glucose in 6 kg of water cannot be determined without knowing the volume of the solution. Molarity is defined as the amount of solute (in mol) divided by the volume of the solution in liters. Without the volume, the molarity of the solution cannot be calculated.
4 mol/0.800 kg
0,4 mol NaCl is 23,376 g.2,85 mol NaCl is 166,554 g to 1L.140 mL solution NaCl 2,85 M contain 0,4 mol NaCl.
20.2 g of CuCl2 = .1502 mol CuCl2 M=mol/L M=.1502 mol/L
4 mol/0.800 kg
The molality of a solution is calculated by dividing the moles of solute by the mass of the solvent in kilograms. In this case, the molality of the CaCl2 solution would be 2 mol/kg, as 6 mol of CaCl2 dissolved in 3 kg of water results in a molality of 2 mol/kg.