0
What else can I help you with?
What is the volume of 19.87 mol of ammonium chloride NHÁCl at STP?
To find the volume of 19.87 mol of NH₄Cl at STP (standard temperature and pressure), we can use the ideal gas law. At STP, 1 mol of gas occupies 22.4 L. Therefore, 19.87 mol of NH₄Cl will occupy 19.87 mol x 22.4 L/mol = 445.888 L.
How do you calculate the volume in liters of 1.50 mol Cl2 at stp?
To calculate the volume of a gas at STP (Standard Temperature and Pressure), you can use the ideal gas law equation: PV = nRT. At STP, the pressure is 1 atm, the temperature is 273 K, and the molar volume of an ideal gas is 22.4 L/mol. Plugging in the values, you can calculate the volume of 1.50 mol of Cl2 at STP.
What is the volume of oxygen that will be used by 12g of Mg to be completely converted into MgO?
The reaction : Mg + O2-----------> MgO The balanced reaction : 2 Mg + O2-----------> 2 MgO that is 2 moles of Mg reacts with one mole of oxygen gas. moles of Mg reacted = 12 g / 24 g mol-1=0.5 mol. Thus the no. of mol of O2 reacted = 0.5 mol /2 =0.25 mol If the gas is at standard temperature and pressure, then Volume of 1 mol of O2 gas = 22.4 dm3 Volume of 0.25 mol of O2 gas = 22.4 x 0.25 dm3= 5.6 dm3 the volume of oxygen that will be used to react completely with 12 g Mg =5.6 dm3 (provided that the gas is at the standard conditions.)
How a box with a volume of 22.4 L contains 1.0 mol of nitrogen and 2.0 mol of hydrogen at 0 and degC. statements is true?
This statement is true. According to the ideal gas law, at 0°C and 1 atm pressure, 1 mol of any ideal gas occupies 22.4 L of volume. Therefore, 1.0 mol of nitrogen would occupy 22.4 L and 2.0 mol of hydrogen would occupy 44.8 L in a 22.4 L box.
What is the volume of 2.22 mol of o2 at STP?
1mol of a gas occupies 24 dm3 at STP, so 2.2mol X 24 mol/dm3 =52.8dm3 or 5280cm3
What does avagadros law say about a gas at STP?
1 mol of any gas has a volume of 22.4 L at STP
What volume will 1.50 mol of C2H4 gas occupy at STP?
1 mole gas = 22.4L 1.5mol C2H4 x 22.4L/mol = 33.6L ethane gas (C2H4)
What is the volume of 19.87 mol of ammonium chloride NHÁCl at STP?
To find the volume of 19.87 mol of NH₄Cl at STP (standard temperature and pressure), we can use the ideal gas law. At STP, 1 mol of gas occupies 22.4 L. Therefore, 19.87 mol of NH₄Cl will occupy 19.87 mol x 22.4 L/mol = 445.888 L.
How do you calculate the volume in liters of 1.50 mol Cl2 at stp?
To calculate the volume of a gas at STP (Standard Temperature and Pressure), you can use the ideal gas law equation: PV = nRT. At STP, the pressure is 1 atm, the temperature is 273 K, and the molar volume of an ideal gas is 22.4 L/mol. Plugging in the values, you can calculate the volume of 1.50 mol of Cl2 at STP.
Which must be the same when comparing 1 mol of oxygen gas O2 with 1 mol of carbon monoxide gas CO?
When comparing 1 mol of oxygen gas (O₂) with 1 mol of carbon monoxide gas (CO), the number of molecules must be the same, as both contain 1 mol. Additionally, both gases will have the same volume under standard temperature and pressure conditions, which is approximately 22.4 liters. However, their molar masses and chemical properties differ significantly.
What is the volume of oxygen that will be used by 12g of Mg to be completely converted into MgO?
The reaction : Mg + O2-----------> MgO The balanced reaction : 2 Mg + O2-----------> 2 MgO that is 2 moles of Mg reacts with one mole of oxygen gas. moles of Mg reacted = 12 g / 24 g mol-1=0.5 mol. Thus the no. of mol of O2 reacted = 0.5 mol /2 =0.25 mol If the gas is at standard temperature and pressure, then Volume of 1 mol of O2 gas = 22.4 dm3 Volume of 0.25 mol of O2 gas = 22.4 x 0.25 dm3= 5.6 dm3 the volume of oxygen that will be used to react completely with 12 g Mg =5.6 dm3 (provided that the gas is at the standard conditions.)
How a box with a volume of 22.4 L contains 1.0 mol of nitrogen and 2.0 mol of hydrogen at 0 and degC. statements is true?
This statement is true. According to the ideal gas law, at 0°C and 1 atm pressure, 1 mol of any ideal gas occupies 22.4 L of volume. Therefore, 1.0 mol of nitrogen would occupy 22.4 L and 2.0 mol of hydrogen would occupy 44.8 L in a 22.4 L box.
What is the volume at 273 K and 1 Bar?
At 273 K (0°C) and 1 bar pressure, the molar volume of an ideal gas is approximately 24.79 L/mol. This value represents the volume occupied by one mole of the gas under these conditions.
What is the volume of 12g of NO2 at STP?
At STP, 1 mole of an ideal gas occupies 22.4 liters. 0.335 mol x 22.4 L = 7.50 L .................. 1 mol
How many liters of oxygen gas are present in 11.3 grams of oxygen gas?
Because oxygen gas (O2) has a molar mass of 32g/mol, 11.3 g * 1/32 mol/g gives about .35 moles. An ideal gas has a volume of 22.4 L/mol at STP, so 11.3 g O2 would have a volume of 7.91 L at STP.
A mixture of gases contains 0.25 mol oxygen gas 0.75 mol nitrogen gas and 1.50 mol carbon dioxide gas at STP The mole fraction of oxygen gas in this mixture is?
At STP (Standard Temperature and Pressure), the volume occupied by 1 mol of any gas is 22.4 L. Thus, 0.25 mol of oxygen gas occupies (0.25 mol) * (22.4 L/mol) = 5.6 L in the mixture. The total volume of the gas mixture can be found as the sum of the individual volumes of oxygen, nitrogen, and carbon dioxide. Then, the mole fraction of oxygen gas is the moles of oxygen gas divided by the total moles of all gases in the mixture.
What is the volumes of gas molecules relative to the total gas volume?
The volume of gas molecules is negligible compared to the total gas volume. Gas molecules themselves occupy a very small fraction of the total volume of the gas, with the majority of the volume being empty space between the molecules.
