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STP (standard temperature and pressure)
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What is the volume of oxygen that will be used by 12g of Mg to be completely converted into MgO?
The reaction : Mg + O2-----------> MgO The balanced reaction : 2 Mg + O2-----------> 2 MgO that is 2 moles of Mg reacts with one mole of oxygen gas. moles of Mg reacted = 12 g / 24 g mol-1=0.5 mol. Thus the no. of mol of O2 reacted = 0.5 mol /2 =0.25 mol If the gas is at standard temperature and pressure, then Volume of 1 mol of O2 gas = 22.4 dm3 Volume of 0.25 mol of O2 gas = 22.4 x 0.25 dm3= 5.6 dm3 the volume of oxygen that will be used to react completely with 12 g Mg =5.6 dm3 (provided that the gas is at the standard conditions.)
What is the volume of one mole of any gas at STP?
At STP, 1 mol or 6.02x10^23 representative particles, of any gas occupies a volume of 22.4 Liters. (chemistry)
What is molar and molal volume?
The molar volume at STP(22.4 L/mol) can be used to calculate the molar mass of the gas.
What is the volume of hydrogen gas when a sample of 9 grams of aluminum metal is added to an excess of hydrochloric acid?
9g Al x (1 mol Al/27g Al) x (3mol H2 / 2 mol Al) x (22.4L / 1 mol H2) = 11.2L H2
What is the volume at STP of a 49.6 gram sample of acetylene gas?
Acetylene is C2H2, with a molar mass of 26g/mol. 49.6g of it = 1.9 moles. At STP, 1 mole of any gas occupies a volume of 22.4 liters, so 1.9 moles at STP would have a volume of 42.56 liters.
What volume will 1.50 mol of C2H4 gas occupy at STP?
1 mole gas = 22.4L 1.5mol C2H4 x 22.4L/mol = 33.6L ethane gas (C2H4)
What does avagadros law say about a gas at STP?
1 mol of any gas has a volume of 22.4 L at STP
What is the volume of oxygen that will be used by 12g of Mg to be completely converted into MgO?
The reaction : Mg + O2-----------> MgO The balanced reaction : 2 Mg + O2-----------> 2 MgO that is 2 moles of Mg reacts with one mole of oxygen gas. moles of Mg reacted = 12 g / 24 g mol-1=0.5 mol. Thus the no. of mol of O2 reacted = 0.5 mol /2 =0.25 mol If the gas is at standard temperature and pressure, then Volume of 1 mol of O2 gas = 22.4 dm3 Volume of 0.25 mol of O2 gas = 22.4 x 0.25 dm3= 5.6 dm3 the volume of oxygen that will be used to react completely with 12 g Mg =5.6 dm3 (provided that the gas is at the standard conditions.)
How many liters of oxygen gas are present in 11.3 grams of oxygen gas?
Because oxygen gas (O2) has a molar mass of 32g/mol, 11.3 g * 1/32 mol/g gives about .35 moles. An ideal gas has a volume of 22.4 L/mol at STP, so 11.3 g O2 would have a volume of 7.91 L at STP.
What is the volumes of gas molecules relative to the total gas volume?
If you are talking about ideal conditions then you can use the ideal gas law: (Pressure)(Volume)=(Number of particles in moles)(R=8.314472 J·K−1·mol−1)(Temperature) or PV=nRT
What is the volume of 12g of NO2 at STP?
At STP, 1 mole of an ideal gas occupies 22.4 liters. 0.335 mol x 22.4 L = 7.50 L .................. 1 mol
If you have mL degrees Celsius and mmHg figure out Volume at STP?
That's going to depend on the substance, which the question neglects to identify. --------------------------------------------------- The volume of any gas at STP (pressure of 1 ATM & temp.: 0oC) is approximately 22.41 L/mol or 22,410 mL/mol. So you need to find out how much gas you have to begin with (# of moles) to find the volume of the gas at STP.
How do you figure out the HNO3 Concentration?
The equation you will need is: Mol of substance 1 * volume of substance 1 = Mol of substance 2 * volume of substance 2
What is the volume of one mole of any gas at STP?
At STP, 1 mol or 6.02x10^23 representative particles, of any gas occupies a volume of 22.4 Liters. (chemistry)
Calculate the density of nitrogen gas, in grams per liter, at STP?
At Standard Temperature and Pressure (STP), which is defined as 0 degrees Celsius (273.15 Kelvin) and 1 atmosphere pressure, the molar volume of an ideal gas is approximately 22.4 liters/mol. The molar mass of nitrogen gas (Nā) is approximately 28.02 grams/mol. To calculate the density (D) of nitrogen gas at STP, you can use the ideal gas law: ļæ½ = Molar mass Molar volume at STP D= Molar volume at STP Molar mass ā ļæ½ = 28.02 ā g/mol 22.4 ā L/mol D= 22.4L/mol 28.02g/mol ā ļæ½ ā 1.25 ā g/L Dā1.25g/L Therefore, the density of nitrogen gas at STP is approximately 1.25 grams per liter.
What is molar and molal volume?
The molar volume at STP(22.4 L/mol) can be used to calculate the molar mass of the gas.
A metal cylinder contains 1 mol of nitrogen gas what will happen to the pressure if another mole of gas is added to the cylinder but the temperature and volume do not change?
The pressure would double in size.
