A)1. H2SO4 is the solute
2. Water is the solvent
3. Molarity = moles of solute / liter of solution = n / V
(Note the case of the letters is important in science. N stands for Normal in chemistry a type of concentration, n stands for number of moles)
Rearrange the formula to find n
n = M x V
Here are the known values,
M = 3.5M
n = x mol
V = 1.00L
Plug it in and solve for n (the number of moles of H2SO4 in the solution)
n = 3.5M x 1.00 L = 3.50 mol of H2SO4
Molecular mass of H2SO4 is 1g/mole H x 2 + 32.1g/mol S + 16g/mol O x 4 = 98.1g/mol H2SO4
mass = number of mole x relative molecular mass
mass = n x 98.1g/mol
mass = 98.1g/mol H2SO4 x 3.50mol H2SO4
= 343g H2SO4 <-answer
0.25 M I had this question also, but I don't remember how I found the answer.
The first solution is more concentrated because it contains 6 moles of H2SO4 per one liter of solution. The second solution is less concentrated because it contains 0.1 moles of H2SO4 in one liter. In equal amounts of each example, the first would have more H2SO4.
Assuming pH on just simple concentration. - log(0.01 M H2SO4) = 2 pH =====
You'll never reach that because 98% H2SO4 is of lower normality: max. 37 N Density 1840 g solution / L solution Molar mass 98 g/mol H2SO4 concentration 980 gH2SO4 / 1000g solution H2SO4 2 equivalent H+/mol H2SO4 All together making: [1840*(980/1000) / 98 ] * 2 = 36.8N H2SO4 Or the other way 'round: 80N = 40M = 40*98(g/mol) = 3920 gH2SO4/L = 3920/(98*100) = 4000 g (solution)/L , which is more than the most concentrated H2SO4 solution can weight
how will make solution for 0.005 h2so4
H2SO4 is more acidic if you have equal molar quantities and the same volume for each (ie. Concentration) as it's diprotic . so for example a solution containing 1moldm-3 of H2SO4 has a [H+]of 2moldm-3 whereas HCL and HNO3 have will have a [H+] of 1moldm-3. [H+] is the concentration of hydrogen ions in a solution and [h+] is a measure of acidity as [H+]=10-ph or rearranged Ph=-log[H+]
The first solution is more concentrated because it contains 6 moles of H2SO4 per one liter of solution. The second solution is less concentrated because it contains 0.1 moles of H2SO4 in one liter. In equal amounts of each example, the first would have more H2SO4.
acids such as HCl, H2SO4 HNO3 etc
Assuming pH on just simple concentration. - log(0.01 M H2SO4) = 2 pH =====
You'll never reach that because 98% H2SO4 is of lower normality: max. 37 N Density 1840 g solution / L solution Molar mass 98 g/mol H2SO4 concentration 980 gH2SO4 / 1000g solution H2SO4 2 equivalent H+/mol H2SO4 All together making: [1840*(980/1000) / 98 ] * 2 = 36.8N H2SO4 Or the other way 'round: 80N = 40M = 40*98(g/mol) = 3920 gH2SO4/L = 3920/(98*100) = 4000 g (solution)/L , which is more than the most concentrated H2SO4 solution can weight
how will make solution for 0.005 h2so4
H2SO4 is more acidic if you have equal molar quantities and the same volume for each (ie. Concentration) as it's diprotic . so for example a solution containing 1moldm-3 of H2SO4 has a [H+]of 2moldm-3 whereas HCL and HNO3 have will have a [H+] of 1moldm-3. [H+] is the concentration of hydrogen ions in a solution and [h+] is a measure of acidity as [H+]=10-ph or rearranged Ph=-log[H+]
Only if it is the same acid. ie. You can have 1.0moldm^-3 H2SO4 (sulfuric acid, in car batteries) and 1.0moldm^-3 HCO3 (carbonic acid, in natural acid rain). Even though they are the same concentration, the sulfuric acid is much stronger.
Molal is the number of mols of solute per kilo of solvent. Molar is the number of mols of solute per litre of solution. If you think those through, you should see that which is greater depends on the density of the solvent.
7 g water doesn't contain 60 g sulfuric acid.
sulphur and hydrogen the molecular formula is H2SO4
H plus ion concentration can be decreased by adding base to the solution. The reduction can also be done by accepting hydrogen ions.
(25.00ml H2SO4)(H2SO4 M) = (22.65ml NaOH)(0.550M) = 0.4983M H2SO4